Math

QuestionYou have \3200toinvestinthreefundswithreturnsof3200 to invest in three funds with returns of 10\%,, 7\%,and, and 5\%$. Invest twice as much in growth as in money market. How to allocate?

Studdy Solution

STEP 1

Assumptions1. The total amount to invest is $3200. The percent return rates for the growth fund, income fund, and money market are10%,7%, and5% respectively3. The amount to be invested in the growth fund is twice the amount to be invested in the money market4. The total investment is distributed among the three funds

STEP 2

Let's denote the amount of money to be invested in the money market as xx. According to the problem, the amount to be invested in the growth fund is twice as much as in the money market, so we denote it as 2x2x. The remaining amount will be invested in the income fund, so we denote it as 3200x3200 -x.

STEP 3

Write down the equation that represents the total amount to be invested.
x+2x+(32003x)=3200x +2x + (3200 -3x) =3200

STEP 4

implify the equation.
4x=32004x =3200

STEP 5

olve the equation for xx.
x=3200/4=800x =3200 /4 =800

STEP 6

Now that we have the value for xx, we can find the amount to be invested in the growth fund and income fund.The amount to be invested in the growth fund is 2x2x.
Growthfundinvestment=2x=2times800=1600Growth\, fund\, investment =2x =2 \\times800 =1600The remaining amount will be invested in the income fund, which is 32003x3200 -3x.
Incomefundinvestment=32003x=32003times800=800Income\, fund\, investment =3200 -3x =3200 -3 \\times800 =800So, the distribution of the 3200investmentacrossthethreefundsis3200 investment across the three funds is 800 in the money market, 1600inthegrowthfund,and1600 in the growth fund, and 800 in the income fund.

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