QuestionWhat is the concentration of a solution made by dissolving $180.0 \mathrm{~g}$ of aluminum hydroxide in $1.50 \mathrm{~L}$ of water?

Studdy Solution

STEP 1

Assumptions1. The mass of solid aluminum hydroxide is180.0 g. The volume of water is1.50 L3. The solution is homogeneous, meaning the aluminum hydroxide is evenly distributed throughout the water4. The concentration of a solution is defined as the amount of solute (in this case, aluminum hydroxide) divided by the amount of solution (in this case, water)

STEP 2

We can calculate the concentration of the solution using the formula $Concentration = \frac{Mass\, of\, solute}{Volume\, of\, solution}$

STEP 3

Now, plug in the given values for the mass of solute and volume of solution to calculate the concentration.
$Concentration = \frac{180.0\, g}{1.50\, L}$

STEP 4

Calculate the concentration of the solution.
$Concentration = \frac{180.0\, g}{1.50\, L} =120.0\, g/L$ The concentration of the solution is120.0 g/L.

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