Math  /  Algebra

Questionpicy (Max 100\%) 3(12xy)(2x7y)3(12 x-y)(2 x-7 y)

Studdy Solution

STEP 1

1. We are given an expression that involves two binomials and a constant factor.
2. The goal is to expand the expression by applying the distributive property (also known as the FOIL method for binomials).

STEP 2

1. Apply the distributive property to expand the product of the binomials.
2. Multiply the expanded expression by the constant factor.

STEP 3

Apply the distributive property to expand the product of the binomials (12xy)(2x7y)(12x - y)(2x - 7y).
- First, multiply the first terms: 12x×2x=24x212x \times 2x = 24x^2. - Next, multiply the outer terms: 12x×(7y)=84xy12x \times (-7y) = -84xy. - Then, multiply the inner terms: y×2x=2xy-y \times 2x = -2xy. - Finally, multiply the last terms: y×(7y)=7y2-y \times (-7y) = 7y^2.
Combine these results:
24x284xy2xy+7y2 24x^2 - 84xy - 2xy + 7y^2

STEP 4

Combine like terms in the expanded expression:
24x286xy+7y2 24x^2 - 86xy + 7y^2

STEP 5

Multiply the entire expanded expression by the constant factor 33:
3(24x286xy+7y2) 3(24x^2 - 86xy + 7y^2)
Distribute the 33 to each term:
72x2258xy+21y2 72x^2 - 258xy + 21y^2
The expanded expression is:
72x2258xy+21y2 \boxed{72x^2 - 258xy + 21y^2}

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