Math  /  Numbers & Operations

Question21012+39122 \frac{10}{12}+3 \frac{9}{12}

Studdy Solution

STEP 1

1. The problem involves the addition of two mixed numbers.
2. The fractions in the mixed numbers have the same denominator, which simplifies the addition process.

STEP 2

1. Convert mixed numbers to improper fractions.
2. Add the improper fractions.
3. Convert the result back to a mixed number if necessary.

STEP 3

Convert the first mixed number 210122 \frac{10}{12} to an improper fraction.
21012=2×12+1012=24+1012=34122 \frac{10}{12} = \frac{2 \times 12 + 10}{12} = \frac{24 + 10}{12} = \frac{34}{12}

STEP 4

Convert the second mixed number 39123 \frac{9}{12} to an improper fraction.
3912=3×12+912=36+912=45123 \frac{9}{12} = \frac{3 \times 12 + 9}{12} = \frac{36 + 9}{12} = \frac{45}{12}

STEP 5

Add the two improper fractions 3412\frac{34}{12} and 4512\frac{45}{12}.
3412+4512=34+4512=7912\frac{34}{12} + \frac{45}{12} = \frac{34 + 45}{12} = \frac{79}{12}

STEP 6

Convert the improper fraction 7912\frac{79}{12} back to a mixed number.
1. Divide 7979 by 1212 to find the whole number part: 79÷12=679 \div 12 = 6 remainder 77.
2. The mixed number is 67126 \frac{7}{12}.

The sum of the mixed numbers is:
6712\boxed{6 \frac{7}{12}}

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