Math  /  Algebra

Questiony=32x3 y = 3\left|2 - \frac{x}{3}\right|

Studdy Solution

STEP 1

What is this asking? This is asking us to understand what this absolute value equation looks like! Watch out! Absolute value can be tricky, so let's make sure we don't forget how it behaves!

STEP 2

1. Understand the absolute value
2. Analyze the equation

STEP 3

Alright, so we've got this equation y=32x3y = 3\left|2 - \frac{x}{3}\right|.
Remember, absolute value means whatever is inside those vertical bars becomes positive!
So, if 2x32 - \frac{x}{3} is positive, it stays the same.
If it's negative, we multiply it by 1-1 to make it positive!

STEP 4

The "pointy part" of the absolute value graph, the **vertex**, happens when the stuff inside the absolute value equals zero.
So, let's set 2x3=02 - \frac{x}{3} = 0.
To solve for xx, let's add x3\frac{x}{3} to both sides to get 2=x32 = \frac{x}{3}.
Then, we multiply both sides by 33 to get x=6x = 6.
When x=6x = 6, y=3263=322=30=0y = 3|2 - \frac{6}{3}| = 3|2 - 2| = 3 \cdot 0 = 0.
So, our **vertex** is at the point (6,0)(6, 0).

STEP 5

When 2x3>02 - \frac{x}{3} > 0, the absolute value doesn't do anything!
So, we have y=3(2x3)y = 3(2 - \frac{x}{3}).
Distributing the 33, we get y=6xy = 6 - x.
This is a line with a slope of 1-1 and a y-intercept of 66.
This happens when x<6x < 6.

STEP 6

When 2x3<02 - \frac{x}{3} < 0, the absolute value flips the sign!
So, we have y=3(1)(2x3)=3(x32)=x6y = 3(-1)(2 - \frac{x}{3}) = 3(\frac{x}{3} - 2) = x - 6.
This is a line with a slope of 11 and a y-intercept of 6-6.
This happens when x>6x > 6.

STEP 7

Imagine the graph.
It's a "V" shape with the point at (6,0)(6, 0).
To the left of the vertex, it's the line y=6xy = 6 - x.
To the right of the vertex, it's the line y=x6y = x - 6.

STEP 8

The graph of the equation y=32x3y = 3\left|2 - \frac{x}{3}\right| is a "V" shape with its vertex at (6,0)(6, 0).
For x<6x < 6, the graph follows the line y=6xy = 6 - x.
For x>6x > 6, it follows the line y=x6y = x - 6.

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