Math  /  Algebra

QuestionWrite the logarithm as a sum or difference of logarithms. Simplify each term as much as possible. log(1000a2+b2)=\log \left(\frac{1000}{\sqrt{a^{2}+b^{2}}}\right)=

Studdy Solution

STEP 1

1. We are given a logarithmic expression and need to express it as a sum or difference of logarithms.
2. We will use logarithmic properties to simplify the expression.
3. The expression involves a division and a square root, which can be simplified using logarithmic identities.

STEP 2

1. Apply the quotient rule for logarithms.
2. Simplify the logarithm of the numerator.
3. Simplify the logarithm of the denominator using the power rule.

STEP 3

Apply the quotient rule for logarithms, which states that:
log(MN)=log(M)log(N)\log\left(\frac{M}{N}\right) = \log(M) - \log(N)
For our expression:
log(1000a2+b2)=log(1000)log(a2+b2)\log\left(\frac{1000}{\sqrt{a^{2}+b^{2}}}\right) = \log(1000) - \log(\sqrt{a^{2}+b^{2}})

STEP 4

Simplify the logarithm of the numerator, log(1000) \log(1000) .
Since 1000=103 1000 = 10^3 , we have:
log(1000)=log(103)=3log(10)\log(1000) = \log(10^3) = 3 \log(10)
And since log(10)=1 \log(10) = 1 , it simplifies to:
3log(10)=33 \log(10) = 3

STEP 5

Simplify the logarithm of the denominator using the power rule, which states:
log(a2+b2)=log((a2+b2)1/2)=12log(a2+b2)\log(\sqrt{a^{2}+b^{2}}) = \log((a^{2}+b^{2})^{1/2}) = \frac{1}{2} \log(a^{2}+b^{2})

STEP 6

Combine the simplified terms from Steps 2 and 3:
log(1000a2+b2)=312log(a2+b2)\log\left(\frac{1000}{\sqrt{a^{2}+b^{2}}}\right) = 3 - \frac{1}{2} \log(a^{2}+b^{2})
This is the expression written as a sum or difference of logarithms, fully simplified.

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