Math

QuestionFind the line equation through (3,1)(3,-1) parallel to y=2x7y=-2x-7. Show your steps.

Studdy Solution

STEP 1

Assumptions1. The line passes through the point (3,1)(3,-1). The line is parallel to the line y=x7y=-x-7
3. The slope of a line parallel to another line is the same as the slope of the original line

STEP 2

First, we need to find the slope of the line that we are given. The equation of the line is in the form y=mx+by = mx + b, where mm is the slope. So, the slope of the line y=2x7y=-2x-7 is 2-2.
m=2m = -2

STEP 3

Since the line we are trying to find is parallel to the line y=2x7y=-2x-7, it will have the same slope. So, the slope of the line we are trying to find is also 2-2.
m=2m' = -2

STEP 4

Now, we need to find the y-intercept of the line we are trying to find. We can use the point-slope form of the line, which is yy1=m(xx1)y - y1 = m'(x - x1), where (x1,y1)(x1, y1) is a point on the line.

STEP 5

Plug in the values for the slope mm' and the point (x1,y1)(x1, y1) into the point-slope form of the line.
y(1)=2(x3)y - (-1) = -2(x -3)

STEP 6

implify the equation to find the y-intercept.
y+1=2x+6y +1 = -2x +6

STEP 7

Rearrange the equation to the slope-intercept form, y=mx+by = mx + b.
y=2x+61y = -2x +6 -1

STEP 8

implify the equation.
y=2x+5y = -2x +5The equation of the line that passes through the point (3,1)(3,-1) and is parallel to the line y=2x7y=-2x-7 is y=2x+5y = -2x +5.

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