Math  /  Algebra

QuestionWrite the equation in the form ax2+bx+c=0a x^{2}+b x+c=0. Then identify the values of a,ba, b, and cc. 2x2x=42 x^{2}-x=-4
Part 1 of 4 2x2x=42 x^{2}-x=-4 in the form ax2+bx+c=0a x^{2}+b x+c=0 is 2x2x+4=02 x^{2}-x+4=0.
Part: 1 / 4
Part 2 of 4 2x2x+4=02 x^{2}-x+4=0 is in the form ax2+bx+c=0a x^{2}+b x+c=0, where a=a= \square

Studdy Solution

STEP 1

1. We need to rewrite the given equation in the standard quadratic form ax2+bx+c=0 ax^2 + bx + c = 0 .
2. We need to identify the coefficients a a , b b , and c c from the rewritten equation.

STEP 2

1. Rewrite the given equation in the form ax2+bx+c=0 ax^2 + bx + c = 0 .
2. Identify the values of a a , b b , and c c .

STEP 3

Start with the given equation:
2x2x=4 2x^2 - x = -4
To rewrite it in the form ax2+bx+c=0 ax^2 + bx + c = 0 , move all terms to one side of the equation:
2x2x+4=0 2x^2 - x + 4 = 0
This is now in the standard quadratic form.

STEP 4

Identify the coefficients a a , b b , and c c from the equation 2x2x+4=0 2x^2 - x + 4 = 0 :
- a=2 a = 2 - b=1 b = -1 - c=4 c = 4
The value of a a is:
a=2 a = 2

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