Math  /  Algebra

QuestionWrite the equation in exponential form.
8. log5125=3\log _{5} 125=3
9. log6255=14\log _{625} 5=\frac{1}{4}
10. log1/264=6\log _{1 / 2} 64=-6

Studdy Solution

STEP 1

What is this asking? We need to rewrite logarithm equations in their equivalent exponential forms. Watch out! Remember the relationship between logs and exponents: logba=c\log_{b} a = c means bc=ab^c = a.
Don't mix up the base, exponent, and result!

STEP 2

1. Convert Problem 8
2. Convert Problem 9
3. Convert Problem 10

STEP 3

We're given log5125=3\log_{5} 125 = 3.
Remember, a logarithm is just another way to write an exponent!

STEP 4

The **base** of our logarithm is 55, the **result** is 33, and the **argument** is 125125.

STEP 5

Rewriting in exponential form gives us 53=1255^3 = 125.
Boom!

STEP 6

We have log6255=14\log_{625} 5 = \frac{1}{4}.
Let's **rock** this conversion!

STEP 7

Our **base** is 625625, the **result** is 14\frac{1}{4}, and the **argument** is 55.

STEP 8

In exponential form, this becomes 62514=5625^{\frac{1}{4}} = 5.
Fractional exponents represent roots, so this makes sense!

STEP 9

We're given log1/264=6\log_{1/2} 64 = -6.
Negative exponents?
No problem!

STEP 10

The **base** is 12\frac{1}{2}, the **result** is 6-6, and the **argument** is 6464.

STEP 11

Rewriting gives us (12)6=64(\frac{1}{2})^{-6} = 64.
Remember, a negative exponent flips the fraction!

STEP 12

Problem 8: 53=1255^3 = 125 Problem 9: 62514=5625^{\frac{1}{4}} = 5 Problem 10: (12)6=64(\frac{1}{2})^{-6} = 64

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