QuestionFind the equation of the horizontal line that goes through the point $(3,-1)$ .

Studdy Solution

STEP 1

Assumptions1. We are asked to find the equation of a horizontal line. . A horizontal line has a slope of0.
3. The line passes through the point $(3,-1)$ .

STEP 2

The general equation of a line is given by $y = mx + c$ , where $m$ is the slope and $c$ is the y-intercept.

STEP 3

For a horizontal line, the slope $m$ is0. So, the equation of the line simplifies to $y = c$ .

STEP 4

The line passes through the point $(3,-1)$ . This means that when $x =3$ , $y = -1$ .

STEP 5

Substitute $y = -1$ into the equation $y = c$ to find the y-intercept $c$ .
$-1 = c$

STEP 6

So, the equation of the horizontal line that passes through the point $(3,-1)$ is $y = -1$ .
The equation of the line is $y = -1$ .

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QuestionFind the equation of the horizontal line that goes through the point $(3,-1)$ .

Studdy Solution

STEP 1

Assumptions1. We are asked to find the equation of a horizontal line. . A horizontal line has a slope of0.
3. The line passes through the point $(3,-1)$ .

STEP 2

The general equation of a line is given by $y = mx + c$ , where $m$ is the slope and $c$ is the y-intercept.

STEP 3

For a horizontal line, the slope $m$ is0. So, the equation of the line simplifies to $y = c$ .

STEP 4

The line passes through the point $(3,-1)$ . This means that when $x =3$ , $y = -1$ .

STEP 5

Substitute $y = -1$ into the equation $y = c$ to find the y-intercept $c$ .
$-1 = c$

STEP 6

So, the equation of the horizontal line that passes through the point $(3,-1)$ is $y = -1$ .
The equation of the line is $y = -1$ .

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QuestionFind the equation of the horizontal line that goes through the point (3,−1)(3,-1)(3,−1).

Studdy Solution

STEP 1

Assumptions1. We are asked to find the equation of a horizontal line. . A horizontal line has a slope of0.3. The line passes through the point (3,−1)(3,-1)(3,−1).

STEP 2

The general equation of a line is given by y=mx+cy = mx + cy=mx+c, where mmm is the slope and ccc is the y-intercept.

STEP 3

For a horizontal line, the slope mmm is0. So, the equation of the line simplifies to y=cy = cy=c.

STEP 4

The line passes through the point (3,−1)(3,-1)(3,−1). This means that when x=3x =3x=3, y=−1y = -1y=−1.

STEP 5

Substitute y=−1y = -1y=−1 into the equation y=cy = cy=c to find the y-intercept ccc.−1=c-1 = c−1=c

STEP 6

So, the equation of the horizontal line that passes through the point (3,−1)(3,-1)(3,−1) is y=−1y = -1y=−1.The equation of the line is y=−1y = -1y=−1.

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QuestionFind the equation of the horizontal line that goes through the point $(3,-1)$ .

Assumptions1. We are asked to find the equation of a horizontal line. . A horizontal line has a slope of0.
3. The line passes through the point $(3,-1)$ .

The general equation of a line is given by $y = mx + c$ , where $m$ is the slope and $c$ is the y-intercept.

For a horizontal line, the slope $m$ is0. So, the equation of the line simplifies to $y = c$ .

The line passes through the point $(3,-1)$ . This means that when $x =3$ , $y = -1$ .

Substitute $y = -1$ into the equation $y = c$ to find the y-intercept $c$ .
$-1 = c$

So, the equation of the horizontal line that passes through the point $(3,-1)$ is $y = -1$ .
The equation of the line is $y = -1$ .