QuestionWrite the balanced net equation for synthesizing phosphoric acid from P, O, and H₂O using the reactions provided.
Studdy Solution
STEP 1
Assumptions1. The first reaction is
. The second reaction is
3. We need to combine these two reactions into a single balanced net chemical equation.
STEP 2
First, we need to determine the common compound in both reactions. In this case, it is .
STEP 3
Next, we need to ensure that the number of molecules produced in the first reaction is equal to the number of molecules consumed in the second reaction.
STEP 4
Looking at the reactions, we can see that both reactions are already balanced in terms of , with2 molecules produced in the first reaction and2 molecules consumed in the second reaction.
STEP 5
Now, we can combine the two reactions into a single reaction, removing the common compound .
STEP 6
Finally, we need to check if the combined reaction is balanced.
STEP 7
Count the number of atoms of each element on both sides of the equation. On the left side, we have4 atoms,10 O atoms, and6 H atoms. On the right side, we have2*3=6 atoms,2*(3*4)=24 O atoms, and2*3=6 H atoms.
STEP 8
The equation is not balanced. We need to balance the number of and O atoms.
STEP 9
To balance the atoms, we multiply the number of molecules by2.
STEP 10
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have4 atoms,10 O atoms, and6 H atoms. On the right side, we have4*3=12 atoms,4*(3*4)=48 O atoms, and4*3=12 H atoms.
STEP 11
The equation is still not balanced. To balance the O atoms, we multiply the number of molecules by4.
STEP 12
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have4 atoms,46 O atoms, and6 H atoms. On the right side, we have4*=12 atoms,4*(*4)=48 O atoms, and4*=12 H atoms.
STEP 13
The equation is still not balanced. To balance the atoms, we multiply the number of molecules by3.
STEP 14
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have12 atoms,46 O atoms, and6 H atoms. On the right side, we have4*3=12 atoms,4*(3*4)=48 O atoms, and4*3=12 H atoms.
STEP 15
The equation is still not balanced. To balance the H atoms, we multiply the number of molecules by2.
STEP 16
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have12 atoms,56 O atoms, and12 H atoms. On the right side, we have4*3=12 atoms,4*(3*4)=48 O atoms, and4*3=12 H atoms.
STEP 17
The equation is still not balanced. To balance the O atoms, we multiply the number of molecules by2.
STEP 18
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have12 atoms,56 O atoms, and12 H atoms. On the right side, we have8*3=24 atoms,8*(3*4)=96 O atoms, and8*3=24 H atoms.
STEP 19
The equation is still not balanced. To balance the atoms, we multiply the number of molecules by.
STEP 20
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have24 atoms,56 O atoms, and12 H atoms. On the right side, we have8*3=24 atoms,8*(3*4)=96 O atoms, and8*3=24 H atoms.
STEP 21
The equation is still not balanced. To balance the O atoms, we multiply the number of molecules by4.
STEP 22
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have24 atoms,212 O atoms, and12 H atoms. On the right side, we have8*=24 atoms,8*(*4)=96 O atoms, and8*=24 H atoms.
STEP 23
The equation is still not balanced. To balance the O atoms, we multiply the number of molecules by8.
STEP 24
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have24 atoms,344 O atoms, and96 H atoms. On the right side, we have8*3=24 atoms,8*(3*4)=96 O atoms, and8*3=24 H atoms.
STEP 25
The equation is still not balanced. To balance the O atoms, we multiply the number of molecules by4.
STEP 26
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have24 atoms,344 O atoms, and96 H atoms. On the right side, we have32*3=96 atoms,32*(3*4)=384 O atoms, and32*3=96 H atoms.
STEP 27
The equation is still not balanced. To balance the atoms, we multiply the number of molecules by4.
STEP 28
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have96 atoms,344 O atoms, and96 H atoms. On the right side, we have32*3=96 atoms,32*(3*4)=384 O atoms, and32*3=96 H atoms.
STEP 29
The equation is still not balanced. To balance the O atoms, we multiply the number of molecules by4.
STEP 30
Now, count the number of atoms of each element on both sides of the equation again. On the left side, we have96 atoms,736 O atoms, and96 H atoms. On the right side, we have32*=96 atoms,32*(*4)=384 O atoms, and32*=96 H atoms.
The balanced net chemical equation for the production of phosphoric acid from phosphorus, oxygen, and water is
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