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Math

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PROBLEM

Simplify these expressions using positive exponents:
a. 29262^{-9} \cdot 2^{-6},
b. 29262^{9} \cdot 2^{6},
c. 515÷535^{15} \div 5^{3},
d. 515÷535^{15} \div 5^{-3},
e. (3)2(-3)^{-2},
f. b2b3\frac{b^{2}}{b^{-3}}.

STEP 1

Assumptions1. We are dealing with exponential notation.
. The base numbers are the same in each expression.
3. The rules of exponents apply.

STEP 2

The rule of exponents states that when you multiply two powers with the same base, you add the exponents. So, we add the exponents in the expression 29262^{-9} \cdot2^{-6}.
2926=29+(6)2^{-9} \cdot2^{-6} =2^{-9 + (-6)}

STEP 3

Now, perform the addition operation in the exponent.
29+(6)=2152^{-9 + (-6)} =2^{-15}

SOLUTION

The rule of exponents states that a negative exponent means that the base is on the wrong side of the fraction line, so you flip the base to the other side. So, we rewrite 2152^{-15} as a fraction with a positive exponent.
215=12152^{-15} = \frac{1}{2^{15}}This is the simplest form of 29262^{-9} \cdot2^{-6} with positive exponents.

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