Math  /  Algebra

QuestionWrite an absolute value equation that represents the graph shown.
Your answer should use the form xa=b|\mathrm{x}-\mathrm{a}|=\mathrm{b} or x+a=b|\mathrm{x}+\mathrm{a}|=\mathrm{b}, where a and b are whole umbers, decimals, or simplified fractions. \square

Studdy Solution

STEP 1

What is this asking? We need to find an absolute value equation that matches the two points, 7-7 and 1-1, on the number line. Watch out! Remember that absolute value equations usually have *two* solutions!
Don't forget the meaning of the variable aa and bb in the requested form.

STEP 2

1. Find the Midpoint
2. Find the Distance
3. Build the Equation

STEP 3

The **midpoint** is the center of the solutions.
Imagine it as the "balancing point" between the two given points on the number line.
To find it, we **add** the two given values and **divide** by 22.
It's like finding the average!

STEP 4

Our points are 7-7 and 1-1.
Let's add them: 7+(1)=8-7 + (-1) = -8.

STEP 5

Now, divide by 22: 8/2=4-8 / 2 = -4.
So, our **midpoint** is 4-4!

STEP 6

The **distance** is how far each point is from the midpoint.
This tells us how "wide" the absolute value graph is.
We can find it by taking the absolute value of the difference between one of the points and the midpoint.

STEP 7

Let's use the point 1-1 and our midpoint 4-4.
The difference is 1(4)-1 - (-4).
Remember subtracting a negative is the same as adding a positive, so 1(4)=1+4=3-1 - (-4) = -1 + 4 = 3.

STEP 8

The absolute value of 33 is 3=3|3| = 3.
So, our **distance** is 33!

STEP 9

Now, let's put it all together!
Remember, the general form is xa=b|x - a| = b, where aa is the **midpoint** and bb is the **distance**.

STEP 10

We found our **midpoint** aa to be 4-4 and our **distance** bb to be 33.
Plugging these values into the general form gives us x(4)=3|x - (-4)| = 3.

STEP 11

Subtracting a negative is the same as adding a positive, so our final equation is x+4=3|x + 4| = 3.
Awesome!

STEP 12

The absolute value equation that represents the graph is x+4=3|x + 4| = 3.

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