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Math

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PROBLEM

Find a polynomial equation with roots at 2,3,5-2, 3, 5.

STEP 1

Assumptions
1. The roots of the polynomial are 2,3,5-2, 3, 5.
2. The polynomial is a cubic polynomial because there are three roots.
3. The polynomial has real coefficients.

STEP 2

To find a polynomial with given roots, we use the fact that if rr is a root of the polynomial, then (xr)(x - r) is a factor of the polynomial.

STEP 3

Write down the factors corresponding to each root.
(x(2)),(x3),(x5) (x - (-2)), (x - 3), (x - 5)

STEP 4

Simplify the factors to make them ready for multiplication.
(x+2),(x3),(x5) (x + 2), (x - 3), (x - 5)

STEP 5

Multiply the factors together to get the polynomial.
(x+2)(x3)(x5) (x + 2)(x - 3)(x - 5)

STEP 6

First, multiply the first two factors (x+2)(x3)(x + 2)(x - 3).
(x+2)(x3)=x23x+2x6 (x + 2)(x - 3) = x^2 - 3x + 2x - 6

STEP 7

Combine like terms from the multiplication.
x23x+2x6=x2x6 x^2 - 3x + 2x - 6 = x^2 - x - 6

STEP 8

Now, multiply the result by the third factor (x5)(x - 5).
(x2x6)(x5) (x^2 - x - 6)(x - 5)

STEP 9

Use the distributive property (also known as the FOIL method for binomials) to multiply the terms.
x35x2x2+5x6x+30 x^3 - 5x^2 - x^2 + 5x - 6x + 30

STEP 10

Combine like terms.
x36x2x+30 x^3 - 6x^2 - x + 30

SOLUTION

The polynomial equation with roots of 2,3,5-2, 3, 5 is:
x36x2x+30=0 x^3 - 6x^2 - x + 30 = 0 This is the required polynomial equation.

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