Math

QuestionDefine a function H(x)H(x) to calculate the cost after a 30% discount on Hector's original amount xx.

Studdy Solution

STEP 1

Assumptions1. The original cost that Hector needs to pay is represented by xx . The "good student discount" is30%
3. The discount is applied to the original cost

STEP 2

We need to find the amount of the discount. We can do this by multiplying the original cost by the discount rate.
Discount=OriginalcosttimesDiscountrateDiscount = Original\, cost \\times Discount\, rate

STEP 3

Now, we can define the function H(x)H(x) as the original cost minus the discount.
H(x)=OriginalcostDiscountH(x) = Original\, cost - Discount

STEP 4

Substituting the formula for the discount from2 into the function H(x)H(x), we getH(x)=x(xtimesDiscountrate)H(x) = x - (x \\times Discount\, rate)

STEP 5

Now, plug in the given value for the discount rate to define the function H(x)H(x).
H(x)=x(xtimes30%)H(x) = x - (x \\times30\%)

STEP 6

Convert the percentage to a decimal value.
30%=0.330\% =0.3H(x)=x(xtimes0.3)H(x) = x - (x \\times0.3)

STEP 7

implify the function H(x)H(x).
H(x)=x0.3xH(x) = x -0.3x

STEP 8

Factor out xx from the function H(x)H(x).
H(x)=x(10.3)H(x) = x(1 -0.3)

STEP 9

implify the function H(x)H(x).
H(x)=.7xH(x) =.7xSo, the function H(x)H(x) that calculates the amount Hector needs to pay after a "good student discount" of 30%30 \% is applied is H(x)=.7xH(x) =.7x.

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