Math  /  Algebra

QuestionWork out the value of ww in this equality: 93×92×9w=9429^{3} \times 9^{2} \times 9^{w}=9^{42}

Studdy Solution

STEP 1

1. The equation involves exponential expressions with the same base.
2. We can use properties of exponents to simplify and solve for w w .

STEP 2

1. Simplify the left side of the equation using properties of exponents.
2. Equate the exponents on both sides of the equation.
3. Solve for w w .

STEP 3

Use the property of exponents that states am×an=am+n a^m \times a^n = a^{m+n} to simplify the left side of the equation:
93×92×9w=93+2+w 9^3 \times 9^2 \times 9^w = 9^{3+2+w}
This simplifies to:
93+2+w=942 9^{3+2+w} = 9^{42}

STEP 4

Since the bases are the same, set the exponents equal to each other:
3+2+w=42 3 + 2 + w = 42

STEP 5

Solve for w w by combining like terms and isolating w w :
5+w=42 5 + w = 42
Subtract 5 from both sides:
w=425 w = 42 - 5 w=37 w = 37
The value of w w is:
37 \boxed{37}

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