QuestionWhich has more atoms: a Co sample with $4.46 \times 10^{24}$ atoms or a 9.04 mole sample of Rb?

Studdy Solution

STEP 1

Assumptions1. The first sample contains $4.46 \times10^{24}$ atoms of Co. . The second sample contains9.04 moles of Rb.
3. Avogadro's number is $6.022 \times10^{23}$ atoms/mole. This is the number of atoms in one mole of any substance.

STEP 2

First, we need to find the number of atoms in the9.04 mole sample of Rb. We can do this by multiplying the number of moles by Avogadro's number.
$Number\, of\, atoms = Number\, of\, moles \\times Avogadro's\, number$

STEP 3

Now, plug in the given values for the number of moles and Avogadro's number to calculate the number of atoms.
$Number\, of\, atoms =9.04\, moles \\times6.022 \times10^{23}\, atoms/mole$

STEP 4

Calculate the number of atoms in the9.04 mole sample of Rb.
$Number\, of\, atoms =9.04 \\times6.022 \times10^{23} =.44 \times10^{24}$

STEP 5

Now that we have the number of atoms in both samples, we can compare them to find out which sample contains the greatest number of atoms.
The first sample contains $4.46 \times10^{24}$ atoms of Co. The second sample contains $5.44 \times10^{24}$ atoms of Rb.
Therefore, the9.04 mole sample of Rb contains the greatest number of atoms.

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