QuestionIdentify the species with 39 protons and 36 electrons from: A) $\mathrm{K}^{+}$ B) $Y$ C) $\mathrm{Ca}^{2+}$ D) $Y^{3+}$ E) $\mathrm{Ar}$ .

Studdy Solution

STEP 1

Assumptions1. The number of protons in an atom determines its atomic number, and hence the element. . The number of electrons in a neutral atom is equal to the number of protons.
3. The charge of an atom is determined by the difference between the number of protons and electrons.
4. The atomic number of the element is39 and it has36 electrons.

STEP 2

First, we need to identify the element. We can do this by looking up the atomic number (number of protons) in the periodic table.
$Element = Atomic\, number$

STEP 3

Plug in the given value for the atomic number to find the element.
$Element =39$

STEP 4

By looking at the periodic table, we find that the element with atomic number39 is Yttrium (Y).

STEP 5

Next, we need to find the charge of the atom. The charge is determined by the difference between the number of protons and electrons.
$Charge = Number\, of\, protons - Number\, of\, electrons$

STEP 6

Plug in the given values for the number of protons and electrons to calculate the charge.
$Charge =39 -36$

STEP 7

Calculate the charge.
$Charge =39 -36 = +3$

STEP 8

Now that we have the element and the charge, we can write the symbol for the species. The symbol for a species is written as the symbol of the element followed by the charge.
$Species = Element^{Charge}$

STEP 9

Plug in the values for the element and the charge to write the symbol for the species.
$Species = Y^{+3}$ The species with39 protons and36 electrons is $Y^{3+}$ .

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QuestionIdentify the species with 39 protons and 36 electrons from: A) $\mathrm{K}^{+}$ B) $Y$ C) $\mathrm{Ca}^{2+}$ D) $Y^{3+}$ E) $\mathrm{Ar}$ .

Studdy Solution

STEP 1

STEP 2

First, we need to identify the element. We can do this by looking up the atomic number (number of protons) in the periodic table.
$Element = Atomic\, number$

STEP 3

Plug in the given value for the atomic number to find the element.
$Element =39$

STEP 4

By looking at the periodic table, we find that the element with atomic number39 is Yttrium (Y).

STEP 5

Next, we need to find the charge of the atom. The charge is determined by the difference between the number of protons and electrons.
$Charge = Number\, of\, protons - Number\, of\, electrons$

STEP 6

Plug in the given values for the number of protons and electrons to calculate the charge.
$Charge =39 -36$

STEP 7

Calculate the charge.
$Charge =39 -36 = +3$

STEP 8

Now that we have the element and the charge, we can write the symbol for the species. The symbol for a species is written as the symbol of the element followed by the charge.
$Species = Element^{Charge}$

STEP 9

Plug in the values for the element and the charge to write the symbol for the species.
$Species = Y^{+3}$ The species with39 protons and36 electrons is $Y^{3+}$ .

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QuestionIdentify the species with 39 protons and 36 electrons from: A) K+\mathrm{K}^{+}K+ B) YYY C) Ca2+\mathrm{Ca}^{2+}Ca2+ D) Y3+Y^{3+}Y3+ E) Ar\mathrm{Ar}Ar.

Studdy Solution

STEP 1

STEP 2

First, we need to identify the element. We can do this by looking up the atomic number (number of protons) in the periodic table.Element=Atomic numberElement = Atomic\, numberElement=Atomicnumber

STEP 3

Plug in the given value for the atomic number to find the element.Element=39Element =39Element=39

STEP 4

By looking at the periodic table, we find that the element with atomic number39 is Yttrium (Y).

STEP 5

Next, we need to find the charge of the atom. The charge is determined by the difference between the number of protons and electrons.Charge=Number of protons−Number of electronsCharge = Number\, of\, protons - Number\, of\, electronsCharge=Numberofprotons−Numberofelectrons

STEP 6

Plug in the given values for the number of protons and electrons to calculate the charge.Charge=39−36Charge =39 -36Charge=39−36

STEP 7

Calculate the charge.Charge=39−36=+3Charge =39 -36 = +3Charge=39−36=+3

STEP 8

Now that we have the element and the charge, we can write the symbol for the species. The symbol for a species is written as the symbol of the element followed by the charge.Species=ElementChargeSpecies = Element^{Charge}Species=ElementCharge

STEP 9

Plug in the values for the element and the charge to write the symbol for the species.Species=Y+3Species = Y^{+3}Species=Y+3The species with39 protons and36 electrons is Y3+Y^{3+}Y3+.

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QuestionIdentify the species with 39 protons and 36 electrons from: A) $\mathrm{K}^{+}$ B) $Y$ C) $\mathrm{Ca}^{2+}$ D) $Y^{3+}$ E) $\mathrm{Ar}$ .

First, we need to identify the element. We can do this by looking up the atomic number (number of protons) in the periodic table.
$Element = Atomic\, number$

Plug in the given value for the atomic number to find the element.
$Element =39$

Next, we need to find the charge of the atom. The charge is determined by the difference between the number of protons and electrons.
$Charge = Number\, of\, protons - Number\, of\, electrons$

Plug in the given values for the number of protons and electrons to calculate the charge.
$Charge =39 -36$

Calculate the charge.
$Charge =39 -36 = +3$

Now that we have the element and the charge, we can write the symbol for the species. The symbol for a species is written as the symbol of the element followed by the charge.
$Species = Element^{Charge}$

Plug in the values for the element and the charge to write the symbol for the species.
$Species = Y^{+3}$ The species with39 protons and36 electrons is $Y^{3+}$ .