Math  /  Algebra

QuestionWhich of the following transformations have occurred to the absolute value parent function to create the graph of k(x)=12(x2)3k(x)=\frac{1}{2}|-(x-2)|-3 ? Select all the apply. - Reflection over the x-axis. Reflection over the yy-axis. Vertical compression Vertical stretch \qquad Horizontal compression Horizontal stretch Translation right Translation left Translation up Translation down

Studdy Solution

STEP 1

What is this asking? This problem is asking us to identify all the ways the basic absolute value graph, x|x|, has been changed to make the new graph k(x)=12(x2)3k(x) = \frac{1}{2}|-(x-2)| - 3. Watch out! Be careful with the signs inside and outside the absolute value!
They can be tricky!

STEP 2

1. Simplify the function
2. Analyze the transformations

STEP 3

We can rewrite the absolute value part of our function.
Remember that anything=anything|-\text{anything}| = |\text{anything}|.
So, we have (x2)=x2 |-(x-2)| = |x-2|.
This makes our function k(x)=12x23k(x) = \frac{1}{2}|x-2| - 3.

STEP 4

The 12\frac{1}{2} in front of the absolute value tells us how much the graph is stretched or compressed *vertically*.
Since 12\frac{1}{2} is between 0 and 1, it's a **vertical compression** by a factor of 12\frac{1}{2}.
Imagine squishing the graph vertically towards the x-axis!

STEP 5

The 2-2 *inside* the absolute value with the xx tells us about a *horizontal* shift.
Since it's (x2)(x-2), we shift the graph **2 units to the right**.
Remember, inside the absolute value, it's the *opposite* of what it looks like! x2x - 2 means move to the *positive* direction.

STEP 6

Finally, the 3-3 *outside* the absolute value tells us about a *vertical* shift.
Since it's 3-3, we shift the graph **3 units down**.

STEP 7

The transformations are: * **Vertical compression** * **Translation right** * **Translation down**

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord