QuestionFind which number is closest to $10$ : A. $\sqrt{98}$ , B. $\sqrt{99}$ , C. $\sqrt{102}$ , D. $\sqrt{97}$ .

Studdy Solution

STEP 1

Assumptions1. We are looking for the square root that is closest to10. . The options are $\sqrt{98}$ , $\sqrt{99}$ , $\sqrt{102}$ , and $\sqrt{97}$ .

STEP 2

We know that $10^2 =100$ . So, we are looking for the square root of a number that is closest to100.

STEP 3

Let's calculate the absolute difference between each option and100.
For option A, $\sqrt{98}$ , the difference is $|100 -98| =2$ .
For option B, $\sqrt{99}$ , the difference is $|100 -99| =1$ .
For option C, $\sqrt{102}$ , the difference is $|100 -102| =2$ .
For option D, $\sqrt{97}$ , the difference is $|100 -97| =3$ .

STEP 4

From the calculations in step3, we can see that the square root of99 has the smallest difference from100.
Therefore, $\sqrt{99}$ is the number that is closest to10.
The answer is B. $\sqrt{99}$ .

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