Math

QuestionWhich method would NOT increase HI\mathrm{HI} production in the reaction: 51.8 kJ+H2+I22HI51.8 \mathrm{~kJ} + \mathrm{H}_{2} + \mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI}? A. add HI\mathrm{HI} B. heat C. add H2\mathrm{H}_{2} D. add I2\mathrm{I}_{2}

Studdy Solution

STEP 1

Assumptions1. The reaction is an equilibrium reaction, which means the rate of the forward reaction equals the rate of the reverse reaction. . The reaction is exothermic, which means it releases heat.
3. Le Chatelier's principle applies, which states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change.

STEP 2

First, we need to understand what each method does to the reaction.A. Adding more HI\mathrm{HI} gas would increase the concentration of the product, which according to Le Chatelier's principle, would shift the reaction to the left (towards the reactants) to re-establish equilibrium.
B. Heating the reaction would add heat to the system. Since the reaction is exothermic (releases heat), according to Le Chatelier's principle, the reaction would shift to the left (towards the reactants) to re-establish equilibrium.
C. Adding more H2\mathrm{H}_{2} gas would increase the concentration of a reactant, which according to Le Chatelier's principle, would shift the reaction to the right (towards the products) to re-establish equilibrium.
. Adding more 2\mathrm{}_{2} gas would also increase the concentration of a reactant, which according to Le Chatelier's principle, would shift the reaction to the right (towards the products) to re-establish equilibrium.

STEP 3

From the analysis in2, we can see that methods A and B would shift the reaction towards the reactants, not the products. Therefore, they would not encourage more product, HI\mathrm{HI}, to form. On the other hand, methods C and D would shift the reaction towards the products, encouraging more product, HI\mathrm{HI}, to form.
Therefore, the method that would NOT encourage more product, HI\mathrm{HI}, to form from the reaction is either A. add HI\mathrm{HI} gas or B. heat the reaction.

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