Math

QuestionWhich expression equals 11y511 y-5? Choose Yes or No for each option: A. 18(88y40)\frac{1}{8}(88 y-40) B. 12(22y10)\frac{1}{2}(22 y-10) C. 3(33y15)3(33 y-15) D. 511y5-11 y

Studdy Solution

STEP 1

Assumptions1. We are given the expression 11y511y -5 . We are asked to find which of the provided options is equivalent to the given expression

STEP 2

Let's start with option A. We need to simplify the expression 18(88y40)\frac{1}{8}(88y -40).

STEP 3

Apply the distributive property to simplify the expression.
18(88y40)=18×88y18×40\frac{1}{8}(88y -40) = \frac{1}{8} \times88y - \frac{1}{8} \times40

STEP 4

Calculate the simplified expression.
18×88y18×40=11y\frac{1}{8} \times88y - \frac{1}{8} \times40 =11y -

STEP 5

The simplified expression for option A is 11y511y -5, which is the same as the given expression. So, option A is correct.

STEP 6

Now, let's move to option B. We need to simplify the expression 12(22y10)\frac{1}{2}(22y -10).

STEP 7

Apply the distributive property to simplify the expression.
12(22y10)=12×22y12×10\frac{1}{2}(22y -10) = \frac{1}{2} \times22y - \frac{1}{2} \times10

STEP 8

Calculate the simplified expression.
12×22y12×10=11y5\frac{1}{2} \times22y - \frac{1}{2} \times10 =11y -5

STEP 9

The simplified expression for option B is 11y511y -5, which is the same as the given expression. So, option B is correct.

STEP 10

Now, let's move to option C. We need to simplify the expression 3(33y15)3(33y -15).

STEP 11

Apply the distributive property to simplify the expression.
3(33y15)=3×33y3×153(33y -15) =3 \times33y -3 \times15

STEP 12

Calculate the simplified expression.
×33y×15=99y45 \times33y - \times15 =99y -45

STEP 13

The simplified expression for option C is 99y4599y -45, which is not the same as the given expression. So, option C is not correct.

STEP 14

Finally, let's move to option D. We need to simplify the expression 11y -11y.

STEP 15

The expression 511y5 -11y is not the same as the given expression 11y511y -5. So, option D is not correct.
The correct options are A and B.

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