Math  /  Algebra

QuestionWhich expression is equivalent to 23(6x+15)?-\frac{2}{3}(6 x+15) ? 4x+104 x+10 4x104 x-10 4x10-4 x-10 4x+10-4 x+10

Studdy Solution

STEP 1

What is this asking? We need to simplify the expression 23(6x+15)-\frac{2}{3}(6x + 15) and find the equivalent expression among the given options. Watch out! Don't forget to distribute the 23-\frac{2}{3} to *both* terms inside the parentheses, and be careful with the signs!

STEP 2

1. Distribute the Fraction
2. Simplify the Terms

STEP 3

Alright, let's **distribute** that 23-\frac{2}{3} to both the 6x6x and the 1515 inside the parentheses.
Remember, distributing means multiplying the term outside the parentheses by *each* term inside!
Why? Because the parentheses tell us that the entire expression inside is being multiplied by the fraction outside.

STEP 4

So, first we have 236x-\frac{2}{3} \cdot 6x.
Let's rewrite 66 as 61\frac{6}{1} so we can multiply the fractions easily: 2361x-\frac{2}{3} \cdot \frac{6}{1}x.
Multiply the numerators together and the denominators together: 2631x=123x-\frac{2 \cdot 6}{3 \cdot 1}x = -\frac{12}{3}x.
Now, simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is **3**: 123x=12÷33÷3x=41x=4x-\frac{12}{3}x = -\frac{12 \div 3}{3 \div 3}x = -\frac{4}{1}x = -4x.

STEP 5

Next, we distribute 23-\frac{2}{3} to 1515.
Again, rewrite 1515 as 151\frac{15}{1}: 23151-\frac{2}{3} \cdot \frac{15}{1}.
Multiply the numerators and denominators: 21531=303-\frac{2 \cdot 15}{3 \cdot 1} = -\frac{30}{3}.
Simplify the fraction by dividing both the numerator and denominator by **3**: 303=30÷33÷3=101=10-\frac{30}{3} = -\frac{30 \div 3}{3 \div 3} = -\frac{10}{1} = -10.

STEP 6

Now, let's put it all together!
We found that 236x=4x-\frac{2}{3} \cdot 6x = -4x and 2315=10-\frac{2}{3} \cdot 15 = -10.
So, our simplified expression is 4x10-4x - 10.
Awesome!

STEP 7

The equivalent expression is 4x10-4x - 10.

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