Math  /  Algebra

QuestionWhich ingution can be used to solve for xx ? 30x5=077x+28=6730x+5=677x+18=6730 x-5=07 \quad 7 x+28=67 \quad 30 x+5=67 \quad 7 x+18=67
Solve for xx. x=x=

Studdy Solution

STEP 1

1. We need to identify the correct equation from the provided options to solve for xx.
2. We will check each equation step-by-step to see which one leads to a valid solution for xx.

STEP 2

1. Verify the first equation: 30x5=0730x - 5 = 07.
2. Verify the second equation: 7x+28=677x + 28 = 67.
3. Verify the third equation: 30x+5=6730x + 5 = 67.
4. Verify the fourth equation: 7x+18=677x + 18 = 67.
5. Solve the valid equation for xx.

STEP 3

Verify the first equation: 30x5=0730x - 5 = 07. Add 5 to both sides: 30x5+5=7+530x - 5 + 5 = 7 + 5 30x=1230x = 12 Divide both sides by 30: x=1230=25x = \frac{12}{30} = \frac{2}{5} This is a valid solution for xx.

STEP 4

Verify the second equation: 7x+28=677x + 28 = 67. Subtract 28 from both sides: 7x+2828=67287x + 28 - 28 = 67 - 28 7x=397x = 39 Divide both sides by 7: x=397=5.5714x = \frac{39}{7} = 5.5714 This is a valid solution for xx.

STEP 5

Verify the third equation: 30x+5=6730x + 5 = 67. Subtract 5 from both sides: 30x+55=67530x + 5 - 5 = 67 - 5 30x=6230x = 62 Divide both sides by 30: x=6230=2.0667x = \frac{62}{30} = 2.0667 This is a valid solution for xx.

STEP 6

Verify the fourth equation: 7x+18=677x + 18 = 67. Subtract 18 from both sides: 7x+1818=67187x + 18 - 18 = 67 - 18 7x=497x = 49 Divide both sides by 7: x=497=7x = \frac{49}{7} = 7 This is a valid solution for xx.

STEP 7

Among the four equations, all provided valid solutions for xx. Therefore, any of the following equations can be used to solve for xx: 30x5=0730x - 5 = 07 7x+28=677x + 28 = 67 30x+5=6730x + 5 = 67 7x+18=677x + 18 = 67
The solutions for xx are: x=25x = \frac{2}{5} x=5.5714x = 5.5714 x=2.0667x = 2.0667 x=7x = 7

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