Math

QuestionIdentify the decomposition reaction among these equations: A. 2NaCl2Na+Cl22 \mathrm{NaCl} \rightarrow 2 \mathrm{Na} + \mathrm{Cl}_{2}, B. 3Na+FeBr33NaBr+Fe3 \mathrm{Na} + \mathrm{FeBr}_{3} \rightarrow 3 \mathrm{NaBr} + \mathrm{Fe}, C. 2Mg+O22MgO2 \mathrm{Mg} + \mathrm{O}_{2} \rightarrow 2 \mathrm{MgO}, D. AgNO3+NaClAgCl+NaNO3\mathrm{AgNO}_{3} + \mathrm{NaCl} \rightarrow \mathrm{AgCl} + \mathrm{NaNO}_{3}.

Studdy Solution

STEP 1

Assumptions1. We are looking for a decomposition reaction. . A decomposition reaction is a type of chemical reaction where one compound breaks down into two or more elements or new compounds.

STEP 2

Let's analyze each option.
A. 2NaCl2Na+Cl22 \mathrm{NaCl} \rightarrow2 \mathrm{Na}+\mathrm{Cl}_{2}This equation shows one compound (NaCl) breaking down into two elements (Na and Cl2). This fits the definition of a decomposition reaction.

STEP 3

Let's continue to analyze the other options to make sure we have the correct answer.
B. 3Na+FeBr33NaBr+Fe3 \mathrm{Na}+\mathrm{FeBr}_{3} \rightarrow3 \mathrm{NaBr}+\mathrm{Fe}This equation shows two reactants (Na and FeBr3) combining to form two new products (NaBr and Fe). This is not a decomposition reaction, but rather a displacement reaction.

STEP 4

Let's continue to analyze the other options.
C. 2Mg+22Mg2 \mathrm{Mg}+\mathrm{}_{2} \rightarrow2 \mathrm{Mg}This equation shows two reactants (Mg and O2) combining to form a new compound (Mg). This is not a decomposition reaction, but rather a synthesis reaction.

STEP 5

Let's analyze the last option.
. AgNO3+NaClAgCl+NaNO3\mathrm{AgNO}_{3}+\mathrm{NaCl} \rightarrow \mathrm{AgCl}+\mathrm{NaNO}_{3}This equation shows two reactants (AgNO3 and NaCl) combining to form two new products (AgCl and NaNO3). This is not a decomposition reaction, but rather a double displacement reaction.

STEP 6

After analyzing all the options, we can conclude that option A is the only one that represents a decomposition reaction.So, the correct answer is A. 2NaCl2Na+Cl22 \mathrm{NaCl} \rightarrow2 \mathrm{Na}+\mathrm{Cl}_{2}

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