Math

Question Which angle(s) is/are cotermineal with 5π3\frac{5 \pi}{3}? A) 5π3-\frac{5 \pi}{3} B) 11π3\frac{11 \pi}{3} C) π3\frac{\pi}{3} D) All of the above

Studdy Solution

STEP 1

Assumptions
1. Two angles are coterminal if they differ by an integer multiple of 2π2\pi.
2. The given angle is 5π3\frac{5\pi}{3}.
3. We need to check if each of the provided angles is coterminal with 5π3\frac{5\pi}{3}.

STEP 2

First, let's define what it means for two angles to be coterminal. Two angles are coterminal if one angle can be obtained by adding or subtracting a full rotation (which is 2π2\pi radians) to the other angle.
Coterminal angle=Given angle±k(2π)\text{Coterminal angle} = \text{Given angle} \pm k(2\pi)
where kk is an integer.

STEP 3

Let's check if angle I, 5π3-\frac{5\pi}{3}, is coterminal with 5π3\frac{5\pi}{3}.
We will add 2π2\pi to 5π3-\frac{5\pi}{3} to see if we can obtain 5π3\frac{5\pi}{3}.
5π3+2π=5π3+6π3-\frac{5\pi}{3} + 2\pi = -\frac{5\pi}{3} + \frac{6\pi}{3}

STEP 4

Calculate the sum to see if it is equal to 5π3\frac{5\pi}{3}.
5π3+6π3=1π3-\frac{5\pi}{3} + \frac{6\pi}{3} = \frac{1\pi}{3}

STEP 5

Since 1π3\frac{1\pi}{3} is not equal to 5π3\frac{5\pi}{3}, we can try subtracting 2π2\pi from 5π3\frac{5\pi}{3} to see if we get 5π3-\frac{5\pi}{3}.
5π32π=5π36π3\frac{5\pi}{3} - 2\pi = \frac{5\pi}{3} - \frac{6\pi}{3}

STEP 6

Calculate the difference to see if it is equal to 5π3-\frac{5\pi}{3}.
5π36π3=1π3\frac{5\pi}{3} - \frac{6\pi}{3} = -\frac{1\pi}{3}

STEP 7

Since 1π3-\frac{1\pi}{3} is not equal to 5π3-\frac{5\pi}{3}, we can conclude that angle I is not coterminal with 5π3\frac{5\pi}{3} by a single rotation. However, we should consider multiple rotations (i.e., k>1k > 1) to see if they can be coterminal.

STEP 8

Let's try adding 2π2\pi multiple times to 5π3-\frac{5\pi}{3} to find a coterminal angle.
5π3+2(2π)=5π3+12π3-\frac{5\pi}{3} + 2(2\pi) = -\frac{5\pi}{3} + \frac{12\pi}{3}

STEP 9

Calculate the sum to see if it is equal to 5π3\frac{5\pi}{3}.
5π3+12π3=7π3-\frac{5\pi}{3} + \frac{12\pi}{3} = \frac{7\pi}{3}

STEP 10

Since 7π3\frac{7\pi}{3} is not equal to 5π3\frac{5\pi}{3}, let's subtract 2π2\pi multiple times from 5π3\frac{5\pi}{3} to find a coterminal angle.
5π32(2π)=5π312π3\frac{5\pi}{3} - 2(2\pi) = \frac{5\pi}{3} - \frac{12\pi}{3}

STEP 11

Calculate the difference to see if it is equal to 5π3-\frac{5\pi}{3}.
5π312π3=7π3\frac{5\pi}{3} - \frac{12\pi}{3} = -\frac{7\pi}{3}

STEP 12

Since 7π3-\frac{7\pi}{3} is not equal to 5π3-\frac{5\pi}{3}, let's continue by adding another 2π2\pi to 5π3-\frac{5\pi}{3}.
5π3+3(2π)=5π3+18π3-\frac{5\pi}{3} + 3(2\pi) = -\frac{5\pi}{3} + \frac{18\pi}{3}

STEP 13

Calculate the sum to see if it is equal to 5π3\frac{5\pi}{3}.
5π3+18π3=13π3-\frac{5\pi}{3} + \frac{18\pi}{3} = \frac{13\pi}{3}

STEP 14

Since 13π3\frac{13\pi}{3} is not equal to 5π3\frac{5\pi}{3}, let's subtract another 2π2\pi from 5π3\frac{5\pi}{3}.
5π33(2π)=5π318π3\frac{5\pi}{3} - 3(2\pi) = \frac{5\pi}{3} - \frac{18\pi}{3}

STEP 15

Calculate the difference to see if it is equal to 5π3-\frac{5\pi}{3}.
5π318π3=13π3\frac{5\pi}{3} - \frac{18\pi}{3} = -\frac{13\pi}{3}

STEP 16

Since 13π3-\frac{13\pi}{3} is not equal to 5π3-\frac{5\pi}{3}, let's try adding 4(2π)4(2\pi) to 5π3-\frac{5\pi}{3}.
5π3+4(2π)=5π3+24π3-\frac{5\pi}{3} + 4(2\pi) = -\frac{5\pi}{3} + \frac{24\pi}{3}

STEP 17

Calculate the sum to see if it is equal to 5π3\frac{5\pi}{3}.
5π3+24π3=19π3-\frac{5\pi}{3} + \frac{24\pi}{3} = \frac{19\pi}{3}

STEP 18

Since 19π3\frac{19\pi}{3} is not equal to 5π3\frac{5\pi}{3}, let's subtract 4(2π)4(2\pi) from 5π3\frac{5\pi}{3}.
5π34(2π)=5π324π3\frac{5\pi}{3} - 4(2\pi) = \frac{5\pi}{3} - \frac{24\pi}{3}

STEP 19

Calculate the difference to see if it is equal to 5π3-\frac{5\pi}{3}.
5π324π3=19π3\frac{5\pi}{3} - \frac{24\pi}{3} = -\frac{19\pi}{3}

STEP 20

Since 19π3-\frac{19\pi}{3} is not equal to 5π3-\frac{5\pi}{3}, we can see that adding or subtracting multiples of 2π2\pi in this manner will not yield 5π3-\frac{5\pi}{3}. However, we can observe that by adding 2π2\pi six times, we get:
5π3+6(2π)=5π3+36π3-\frac{5\pi}{3} + 6(2\pi) = -\frac{5\pi}{3} + \frac{36\pi}{3}

STEP 21

Calculate the sum to see if it is equal to 5π3\frac{5\pi}{3}.
5π3+36π3=31π3-\frac{5\pi}{3} + \frac{36\pi}{3} = \frac{31\pi}{3}

STEP 22

Since 31π3\frac{31\pi}{3} is not equal to 5π3\frac{5\pi}{3}, we can subtract 2π2\pi six times from 5π3\frac{5\pi}{3}.
5π36(2π)=5π336π3\frac{5\pi}{3} - 6(2\pi) = \frac{5\pi}{3} - \frac{36\pi}{3}

STEP 23

Calculate the difference to see if it is equal to 5π3-\frac{5\pi}{3}.
5π336π3=31π3\frac{5\pi}{3} - \frac{36\pi}{3} = -\frac{31\pi}{3}

STEP 24

Since 31π3-\frac{31\pi}{3} is not equal to 5π3-\frac{5\pi}{3}, we can conclude that no matter how many times we add or subtract 2π2\pi, we will not get 5π3-\frac{5\pi}{3} as a coterminal angle with 5π3\frac{5\pi}{3}.

STEP 25

Now let's check angle II, 11π3\frac{11\pi}{3}, to see if it is coterminal with 5π3\frac{5\pi}{3}.
We can subtract 2π2\pi from 11π3\frac{11\pi}{3} to see if we can obtain 5π3\frac{5\pi}{3}.
11π32π=11π36π3\frac{11\pi}{3} - 2\pi = \frac{11\pi}{3} - \frac{6\pi}{3}

STEP 26

Calculate the difference to see if it is equal to 5π3\frac{5\pi}{3}.
11π36π3=5π3\frac{11\pi}{3} - \frac{6\pi}{3} = \frac{5\pi}{3}

STEP 27

Since 5π3\frac{5\pi}{3} is equal to 5π3\frac{5\pi}{3}, we can conclude that angle II, 11π3\frac{11\pi}{3}, is coterminal with 5π3\frac{5\pi}{3}.

STEP 28

Finally, let's check angle III, π3\frac{\pi}{3}, to see if it is coterminal with 5π3\frac{5\pi}{3}.
We can add 2π2\pi to π3\frac{\pi}{3} to see if we can obtain 5π3\frac{5\pi}{3}.
π3+2π=π3+6π3\frac{\pi}{3} + 2\pi = \frac{\pi}{3} + \frac{6\pi}{3}

STEP 29

Calculate the sum to see if it is equal to 5π3\frac{5\pi}{3}.
π3+6π3=7π3\frac{\pi}{3} + \frac{6\pi}{3} = \frac{7\pi}{3}

STEP 30

Since 7π3\frac{7\pi}{3} is not equal to 5π3\frac{5\pi}{3}, we can conclude that angle III, π3\frac{\pi}{3}, is not coterminal with 5π3\frac{5\pi}{3}.
The only angle that is coterminal with 5π3\frac{5\pi}{3} is angle II, 11π3\frac{11\pi}{3}. Therefore, the correct answer is:
B) II only

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