QuestionMixing $50 \mathrm{~mL}$ of water at $100^{\circ} \mathrm{C}$ with $50 \mathrm{~mL}$ at $40^{\circ} \mathrm{C}$ should yield $70^{\circ} \mathrm{C}$ . Why is it $65^{\circ} \mathrm{C}$ ? A. Energy lost B. Energy absorbed C. Thermometer error.

Studdy Solution

STEP 1

Assumptions1. The initial volume of water at $100^{\circ} \mathrm{C}$ is $50 \mathrm{~m}$ . . The initial volume of water at $40^{\circ} \mathrm{C}$ is $50 \mathrm{~m}$ .
3. The final temperature of the mixture should be $70^{\circ} \mathrm{C}$ .
4. The thermometer reads $65^{\circ} \mathrm{C}$ .
5. The temperature difference is not due to the thermometer's error.

STEP 2

First, let's understand the concept of heat transfer. When two bodies with different temperatures come into contact, heat flows from the hotter body to the cooler one until they reach thermal equilibrium, i.e., they have the same temperature.

STEP 3

In this case, when $50 \mathrm{~m}$ of water at $100^{\circ} \mathrm{C}$ is combined with $50 \mathrm{~m}$ of water at $40^{\circ} \mathrm{C}$ , heat should flow from the hotter water to the cooler water until they reach a common temperature.

STEP 4

Assuming no heat is lost or gained from the surroundings, the final temperature of the mixture should be the average of the initial temperatures of the two water samples, which is $70^{\circ} \mathrm{C}$ .
$Final\, temperature = (Initial\, temperature\, of\, hot\, water + Initial\, temperature\, of\, cold\, water) /2$

STEP 5

However, the thermometer reads $65^{\circ} \mathrm{C}$ , which is $5^{\circ} \mathrm{C}$ lower than the expected temperature.

STEP 6

This discrepancy can be explained by considering the heat exchange with the surroundings. When the hot and cold water are mixed, some heat could be lost to the environment (beaker and air).

STEP 7

Therefore, the correct answer is (A) Energy is lost to the environment (beaker and air). This heat loss to the surroundings would cause the final temperature of the water mixture to be lower than expected.

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QuestionMixing $50 \mathrm{~mL}$ of water at $100^{\circ} \mathrm{C}$ with $50 \mathrm{~mL}$ at $40^{\circ} \mathrm{C}$ should yield $70^{\circ} \mathrm{C}$ . Why is it $65^{\circ} \mathrm{C}$ ? A. Energy lost B. Energy absorbed C. Thermometer error.

Studdy Solution

STEP 1

STEP 2

First, let's understand the concept of heat transfer. When two bodies with different temperatures come into contact, heat flows from the hotter body to the cooler one until they reach thermal equilibrium, i.e., they have the same temperature.

STEP 3

In this case, when $50 \mathrm{~m}$ of water at $100^{\circ} \mathrm{C}$ is combined with $50 \mathrm{~m}$ of water at $40^{\circ} \mathrm{C}$ , heat should flow from the hotter water to the cooler water until they reach a common temperature.

STEP 4

STEP 5

However, the thermometer reads $65^{\circ} \mathrm{C}$ , which is $5^{\circ} \mathrm{C}$ lower than the expected temperature.

STEP 6

This discrepancy can be explained by considering the heat exchange with the surroundings. When the hot and cold water are mixed, some heat could be lost to the environment (beaker and air).

STEP 7

Therefore, the correct answer is (A) Energy is lost to the environment (beaker and air). This heat loss to the surroundings would cause the final temperature of the water mixture to be lower than expected.

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Studdy Solution

STEP 1

STEP 2

First, let's understand the concept of heat transfer. When two bodies with different temperatures come into contact, heat flows from the hotter body to the cooler one until they reach thermal equilibrium, i.e., they have the same temperature.

STEP 3

In this case, when 50 m50 \mathrm{~m}50 m of water at 100∘C100^{\circ} \mathrm{C}100∘C is combined with 50 m50 \mathrm{~m}50 m of water at 40∘C40^{\circ} \mathrm{C}40∘C, heat should flow from the hotter water to the cooler water until they reach a common temperature.

STEP 4

STEP 5

However, the thermometer reads 65∘C65^{\circ} \mathrm{C}65∘C, which is 5∘C5^{\circ} \mathrm{C}5∘C lower than the expected temperature.

STEP 6

This discrepancy can be explained by considering the heat exchange with the surroundings. When the hot and cold water are mixed, some heat could be lost to the environment (beaker and air).

STEP 7

Therefore, the correct answer is (A) Energy is lost to the environment (beaker and air). This heat loss to the surroundings would cause the final temperature of the water mixture to be lower than expected.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

In this case, when $50 \mathrm{~m}$ of water at $100^{\circ} \mathrm{C}$ is combined with $50 \mathrm{~m}$ of water at $40^{\circ} \mathrm{C}$ , heat should flow from the hotter water to the cooler water until they reach a common temperature.

However, the thermometer reads $65^{\circ} \mathrm{C}$ , which is $5^{\circ} \mathrm{C}$ lower than the expected temperature.