QuestionFind $y$ in the equation $6.4(3) + 2.8y = 44.4$ .

Studdy Solution

STEP 1

Assumptions1. The equation is $6.4x +.8y =44.4$ . The value of $x$ is given as $3$
3. We are asked to find the value of $y$

STEP 2

First, we need to substitute the given value of $x$ into the equation. $6.4x +2.8y =44.4$ becomes $6.4* +2.8y =44.4$

STEP 3

Now, calculate the value of $6.3$ .
$6.3 =19.2$ So the equation becomes $19.2 +2.8y =44.$

STEP 4

Next, we need to isolate $y$ in the equation. We can do this by subtracting $19.2$ from both sides of the equation.
$19.2 +2.8y -19.2 =44.4 -19.2$ This simplifies to $2.8y =44.4 -19.2$

STEP 5

Calculate the value of $44.4 -19.2$ .
$44.4 -19.2 =25.2$ So the equation becomes $2.8y =25.2$

STEP 6

Finally, to find the value of $y$ , we need to divide both sides of the equation by $2.8$ .
$y = \frac{25.2}{2.8}$

STEP 7

Calculate the value of $\frac{25.2}{2.}$ .
$y = \frac{25.2}{2.} =9$ The value of $y$ is $9$ when $x=3$ in the equation $6.4x +2.y =44.4$ .

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