Math  /  Algebra

QuestionWhat is the value of cc in the equation below?
5552=ab=c\frac{5^5}{5^2} = a^b = c

Studdy Solution

STEP 1

What is this asking? We're asked to find the final value (cc) of an expression where we divide two exponents with the same base, then rewrite the result as a different power, and finally compute the numerical value. Watch out! Don't mix up the rules of exponents!
Remember, when dividing exponents with the same base, we *subtract* the powers, not divide them.

STEP 2

1. Simplify the fraction
2. Rewrite as a power of a different base
3. Calculate the final value

STEP 3

Alright, let's **start** with our awesome fraction: 5552\frac{5^5}{5^2}.
Remember the rule: when we divide exponents with the same base, we subtract the powers.
Why? Because we're essentially dividing out common factors.
It's like simplifying a fraction!
We're dividing both the top and bottom by 525^2.

STEP 4

So, we have 5552=5253521=531=53\frac{5^5}{5^2} = \frac{5^2 \cdot 5^3}{5^2 \cdot 1} = \frac{5^3}{1} = 5^3.
We're left with 55 raised to the power of 52=35-2=3, which is 535^3.

STEP 5

The problem says ab=53a^b = 5^3.
We need to find a value for cc where c=abc=a^b.
Notice something cool: the problem doesn't actually say that *a* and *b* have to be different from 5 and 3!
So let's just keep it simple.

STEP 6

We can just say a=5a=5 and b=3b=3.
That fits perfectly!
So, we have ab=53a^b = 5^3.

STEP 7

Now, we just need to **calculate** 535^3.
This means 55 multiplied by itself three times: 5555 \cdot 5 \cdot 5.

STEP 8

Let's do it step by step: 55=255 \cdot 5 = \textbf{25}.
Then, 255=12525 \cdot 5 = \textbf{125}.
So, 53=1255^3 = \textbf{125}.
Since c=ab=53c = a^b = 5^3, we have c=125c = \textbf{125}.

STEP 9

Therefore, the value of cc is 125\textbf{125}.

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