Math  /  Geometry

QuestionWhat is the perimeter, in units, of polygon EFGHJK?

Studdy Solution

STEP 1

What is this asking? We need to find the total length around the polygon EFGHJK, which means adding up the lengths of all its sides! Watch out! Make sure to count the grid units carefully and don't mix up xx and yy coordinates.

STEP 2

1. Find the length of each side
2. Add all side lengths together

STEP 3

Let's **start** with side EF.
The coordinates of E are (22, 44) and F are (44, 44).
Since the yy-coordinates are the same, we only look at the difference in xx-coordinates.
The length of EF is 42=2=2|4 - 2| = |2| = 2 units.

STEP 4

Next, side FG.
The coordinates of F are (44, 44) and G are (44, 6-6).
Since the xx-coordinates are the same, we look at the difference in yy-coordinates.
The length of FG is 4(6)=4+6=10=10|4 - (-6)| = |4 + 6| = |10| = 10 units.

STEP 5

Now, side GH.
The coordinates of G are (44, 6-6) and H are (6-6, 6-6).
Since the yy-coordinates are the same, we look at the difference in xx-coordinates.
The length of GH is 4(6)=4+6=10=10|4 - (-6)| = |4 + 6| = |10| = 10 units.

STEP 6

On to side HJ.
The coordinates of H are (6-6, 6-6) and J are (6-6, 44).
Since the xx-coordinates are the same, we look at the difference in yy-coordinates.
The length of HJ is 64=10=10|-6 - 4| = |-10| = 10 units.

STEP 7

Almost there!
Side JK.
The coordinates of J are (6-6, 44) and K are (00, 44).
Since the yy-coordinates are the same, we look at the difference in xx-coordinates.
The length of JK is 60=6=6|-6 - 0| = |-6| = 6 units.

STEP 8

Last one, side KE.
The coordinates of K are (00, 44) and E are (22, 44).
Since the yy-coordinates are the same, we look at the difference in xx-coordinates.
The length of KE is 02=2=2|0 - 2| = |-2| = 2 units.

STEP 9

Now, we **add** up all the side lengths to find the **perimeter**: 2+10+10+10+6+2=402 + 10 + 10 + 10 + 6 + 2 = 40 units.

STEP 10

The perimeter of polygon EFGHJK is **40** units.

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