QuestionWhat is the Law of Mass Action for the reaction CO(g) + Cl₂(g) ⇌ COCl₂(g)? Choose the correct expression for Kc.

Studdy Solution

STEP 1

Assumptions1. The reaction is at equilibrium. . The Law of Mass Action applies, which states that the rate of a chemical reaction is directly proportional to the product of the molar concentrations of the reactants, each raised to the power of its stoichiometric coefficient in the balanced chemical equation.
3. The brackets denote molar concentrations of the species at equilibrium.
4. The equilibrium constant is denoted by Kc.

STEP 2

The Law of Mass Action for a general reaction can be written as $aA + bB \rightleftharpoons cC + d$ The equilibrium constant expression is $K_c = \frac{[C]^c []^d}{[A]^a [B]^b}$

STEP 3

Now, let's write the Law of Mass Action for the given reaction $CO(g) + Cl2(g) \rightleftharpoons COCl2(g)$

STEP 4

The equilibrium constant expression for the given reaction is $K_c = \frac{[COCl2]}{[CO][Cl2]}$ Therefore, the correct answer is A. $\mathrm{K}_{\mathrm{c}}=\frac{\left[\mathrm{COCl}_{2}\right]}{[\mathrm{CO}]\left[\mathrm{Cl}_{2}\right]}$

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