Math

QuestionFind the 7th term in the sequence given by an=3(3)(n1)a_{n}=-3 \cdot(3)^{(n-1)}. Options: A. 6561 B. -6561 C. -2187 D. 2187

Studdy Solution

STEP 1

Assumptions1. The explicit formula for the geometric sequence is given by an=3(3)(n1)a_{n}=-3 \cdot(3)^{(n-1)} . We are asked to find the7th term in the sequence, i.e., a7a_{7}

STEP 2

To find the7th term in the sequence, we substitute n=7n=7 into the explicit formula.
a7=()(71)a_{7}=- \cdot()^{(7-1)}

STEP 3

implify the exponent in the formula.
a7=3(3)6a_{7}=-3 \cdot(3)^{6}

STEP 4

Calculate the value of 363^{6}.
36=7293^{6} =729So, the formula becomesa7=3729a_{7}=-3 \cdot729

STEP 5

Finally, calculate the7th term in the sequence.
a7=3729=2187a_{7}=-3 \cdot729 = -2187So, the7th term in the sequence is -2187.The correct answer is C. -2187.

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