Math

QuestionFind the 47th term of the sequence given by an=11+(n1)(3)a_{n}=-11+(n-1)(-3). Options: A. -149 B. -152 C. 127 D. -138

Studdy Solution

STEP 1

Assumptions1. The explicit formula for the arithmetic sequence is an=11+(n1)(3)a_{n}=-11+(n-1)(-3). We are looking for the47th term of the sequence, i.e., n=47n=47

STEP 2

The explicit formula for an arithmetic sequence is given as an=a1+(n1)da_{n}=a_{1}+(n-1)d, where a1a_{1} is the first term, dd is the common difference, and nn is the term number. In our case, the given formula is an=11+(n1)()a_{n}=-11+(n-1)(-).

STEP 3

We can see that the first term a1a_{1} is -11 and the common difference dd is -3. We are asked to find the47th term, so we substitute n=47n=47 into the formula.
a47=11+(471)(3)a_{47}=-11+(47-1)(-3)

STEP 4

First, simplify the expression inside the parentheses.
a47=11+(46)(3)a_{47}=-11+(46)(-3)

STEP 5

Next, perform the multiplication.
a47=11+(138)a_{47}=-11+(-138)

STEP 6

Finally, perform the addition to find the47th term.
a47=11138=149a_{47}=-11-138=-149So, the47th term of the arithmetic sequence is -149.
The correct answer is A. -149.

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