QuestionWhat melide is formed when $^{50} \mathrm{Sr}$ undergoes $\beta$ decay?

Studdy Solution

STEP 1

Assumptions1. The initial atom is ${ }^{50} \mathrm{Sr}$ (Strontium-50) . The atom undergoes $\beta$ decay3. In $\beta$ decay, a neutron in the nucleus is converted into a proton and an electron. The electron is emitted as a beta particle.

STEP 2

First, we need to understand what happens during $\beta$ decay. In $\beta$ decay, a neutron in the nucleus of an atom is converted into a proton and an electron. The electron is then emitted from the nucleus as a beta particle.
$n \rightarrow p + e^-$

STEP 3

Now, we can apply this to our specific atom, ${ }^{50} \mathrm{Sr}$ . Strontium-50 has38 protons (since the atomic number of Sr is38) and12 neutrons (since the atomic mass number is50, and50 -38 =12).

STEP 4

When a neutron is converted into a proton during $\beta$ decay, the number of protons in the nucleus increases by1, and the number of neutrons decreases by1. This means that the atomic number of the atom increases by1, while the atomic mass number stays the same (since a proton has been added and a neutron has been removed).

STEP 5

So, after $\beta$ decay, our atom will have39 protons and11 neutrons. The atomic mass number will still be50 (since39 +11 =50).

STEP 6

The atom with an atomic number of39 is Yttrium (Y). So, the atom formed when ${ }^{50} \mathrm{Sr}$ undergoes $\beta$ decay is ${ }^{50} \mathrm{Y}$ .
The nuclide formed when ${ }^{50} \mathrm{Sr}$ undergoes $\beta$ decay is ${ }^{50} \mathrm{Y}$ .

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QuestionWhat melide is formed when $^{50} \mathrm{Sr}$ undergoes $\beta$ decay?

Studdy Solution

STEP 1

Assumptions1. The initial atom is ${ }^{50} \mathrm{Sr}$ (Strontium-50) . The atom undergoes $\beta$ decay3. In $\beta$ decay, a neutron in the nucleus is converted into a proton and an electron. The electron is emitted as a beta particle.

STEP 2

First, we need to understand what happens during $\beta$ decay. In $\beta$ decay, a neutron in the nucleus of an atom is converted into a proton and an electron. The electron is then emitted from the nucleus as a beta particle.
$n \rightarrow p + e^-$

STEP 3

Now, we can apply this to our specific atom, ${ }^{50} \mathrm{Sr}$ . Strontium-50 has38 protons (since the atomic number of Sr is38) and12 neutrons (since the atomic mass number is50, and50 -38 =12).

STEP 4

STEP 5

So, after $\beta$ decay, our atom will have39 protons and11 neutrons. The atomic mass number will still be50 (since39 +11 =50).

STEP 6

The atom with an atomic number of39 is Yttrium (Y). So, the atom formed when ${ }^{50} \mathrm{Sr}$ undergoes $\beta$ decay is ${ }^{50} \mathrm{Y}$ .
The nuclide formed when ${ }^{50} \mathrm{Sr}$ undergoes $\beta$ decay is ${ }^{50} \mathrm{Y}$ .

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QuestionWhat melide is formed when 50Sr^{50} \mathrm{Sr}50Sr undergoes β\betaβ decay?

Studdy Solution

STEP 1

Assumptions1. The initial atom is 50Sr{ }^{50} \mathrm{Sr}50Sr (Strontium-50) . The atom undergoes β\betaβ decay3. In β\betaβ decay, a neutron in the nucleus is converted into a proton and an electron. The electron is emitted as a beta particle.

STEP 2

First, we need to understand what happens during β\betaβ decay. In β\betaβ decay, a neutron in the nucleus of an atom is converted into a proton and an electron. The electron is then emitted from the nucleus as a beta particle.n→p+e−n \rightarrow p + e^-n→p+e−

STEP 3

Now, we can apply this to our specific atom, 50Sr{ }^{50} \mathrm{Sr}50Sr. Strontium-50 has38 protons (since the atomic number of Sr is38) and12 neutrons (since the atomic mass number is50, and50 -38 =12).

STEP 4

STEP 5

So, after β\betaβ decay, our atom will have39 protons and11 neutrons. The atomic mass number will still be50 (since39 +11 =50).

STEP 6

The atom with an atomic number of39 is Yttrium (Y). So, the atom formed when 50Sr{ }^{50} \mathrm{Sr}50Sr undergoes β\betaβ decay is 50Y{ }^{50} \mathrm{Y}50Y.The nuclide formed when 50Sr{ }^{50} \mathrm{Sr}50Sr undergoes β\betaβ decay is 50Y{ }^{50} \mathrm{Y}50Y.

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QuestionWhat melide is formed when $^{50} \mathrm{Sr}$ undergoes $\beta$ decay?

Assumptions1. The initial atom is ${ }^{50} \mathrm{Sr}$ (Strontium-50) . The atom undergoes $\beta$ decay3. In $\beta$ decay, a neutron in the nucleus is converted into a proton and an electron. The electron is emitted as a beta particle.

First, we need to understand what happens during $\beta$ decay. In $\beta$ decay, a neutron in the nucleus of an atom is converted into a proton and an electron. The electron is then emitted from the nucleus as a beta particle.
$n \rightarrow p + e^-$

Now, we can apply this to our specific atom, ${ }^{50} \mathrm{Sr}$ . Strontium-50 has38 protons (since the atomic number of Sr is38) and12 neutrons (since the atomic mass number is50, and50 -38 =12).

So, after $\beta$ decay, our atom will have39 protons and11 neutrons. The atomic mass number will still be50 (since39 +11 =50).

The atom with an atomic number of39 is Yttrium (Y). So, the atom formed when ${ }^{50} \mathrm{Sr}$ undergoes $\beta$ decay is ${ }^{50} \mathrm{Y}$ .
The nuclide formed when ${ }^{50} \mathrm{Sr}$ undergoes $\beta$ decay is ${ }^{50} \mathrm{Y}$ .