Math

QuestionWhat element has an ion with configuration 1s22s22p63s23p64s23d104p65s24d105p61 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{2} 4 d^{10} 5 p^{6} (or [Xe]) and a -2 charge? Provide the symbol.

Studdy Solution

STEP 1

Assumptions1. The electronic configuration given is 1ssp63s3p64s3d104p65s4d105p61 s^{} s^{} p^{6}3 s^{}3 p^{6}4 s^{}3 d^{10}4 p^{6}5 s^{}4 d^{10}5 p^{6} (or [Xe]). . The ion has a charge of -.

STEP 2

First, we need to understand that the electronic configuration given is for an ion, not a neutral atom. The ion has a -2 charge, which means it has gained2 electrons compared to the neutral atom.

STEP 3

The electronic configuration given is equivalent to the noble gas Xenon ([Xe]). This means that the neutral atom has the same electronic configuration as Xenon.

STEP 4

However, since the ion has a -2 charge, it means the neutral atom has2 electrons less than Xenon.

STEP 5

The atomic number of Xenon is54, which means it has54 electrons in its neutral state. Therefore, the neutral atom we are looking for has54 -2 =52 electrons.

STEP 6

The atomic number of an element is equal to the number of electrons in its neutral state. Therefore, the atomic number of the element we are looking for is52.

STEP 7

Looking at the periodic table, the element with atomic number52 is Tellurium (Te).
The symbol for the element is Te.

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