Math  /  Algebra

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Use synthetic division to find the result when 2x417x3+26x2+26x22 x^{4}-17 x^{3}+26 x^{2}+26 x-2 is divided by x6x-6. If there is a remainder, express the result in the form q(x)+r(x)b(x)q(x)+\frac{r(x)}{b(x)}. Answer Altempit out of 5

Studdy Solution

STEP 1

What is this asking? We need to divide a big polynomial by x6x - 6 using synthetic division and write the answer with any remainder. Watch out! Remember to use the *root* associated with the divisor, not the divisor itself, in synthetic division!
Also, keep those signs straight!

STEP 2

1. Set up the synthetic division.
2. Perform the synthetic division.
3. Write the result.

STEP 3

Since we're dividing by x6x - 6, our **root** is x=6x = 6.
This is what we'll use in our synthetic division setup.
Remember, it's x6=0x - 6 = 0, so x=6x = 6.
Super important!

STEP 4

Now, let's grab the **coefficients** from our big polynomial 2x417x3+26x2+26x22x^4 - 17x^3 + 26x^2 + 26x - 2.
They are **2**, **-17**, **26**, **26**, and **-2**.
Write them down in a row.

STEP 5

Draw a little "L" shape to the left of our coefficients, with the **root**, 66, on the outside.
It looks like this:
621726262\begin{array}{cccccc} 6 & 2 & -17 & 26 & 26 & -2 \\ \end{array}

STEP 6

Bring that first coefficient, **2**, straight down below the line.
6217262622\begin{array}{cccccc} 6 & 2 & -17 & 26 & 26 & -2 \\ & 2 & & & & \end{array}

STEP 7

Now, multiply the **root**, 66, by the number we just brought down, **2**.
That gives us 62=126 \cdot 2 = 12.
Write that **12** under the next coefficient, **-17**.
Add those together: 17+12=5-17 + 12 = -5.
Write the result, **-5**, below the line.
62172626225\begin{array}{c c c c c c} 6 & 2 & -17 & 26 & 26 & -2 \\ \hline & 2 & -5 & & & \end{array}Keep going!
Multiply the **root**, 66, by **-5** to get 30-30.
Add that to **26**: 26+(30)=426 + (-30) = -4.
621726262254\begin{array}{cccccc} 6 & 2 & -17 & 26 & 26 & -2 \\ 2 & -5 & -4 & & \end{array}Multiply 66 by 4-4 to get 24-24.
Add that to **26**: 26+(24)=226 + (-24) = 2.
6217262622542\begin{array}{cccccc} 6 & 2 & -17 & 26 & 26 & -2 \\ & 2 & -5 & -4 & 2 & \end{array}Finally, multiply 66 by 22 to get 1212.
Add that to **-2**: 2+12=10-2 + 12 = 10.
621726262254210\begin{array}{cccccc} 6 & 2 & -17 & 26 & 26 & -2 \\ & 2 & -5 & -4 & 2 & 10 \end{array}

STEP 8

Those numbers below the line are the coefficients of our quotient, and the last number is the remainder.
Since we started with an x4x^4 term and divided by an xx term, our quotient starts with an x3x^3 term.
So, our quotient is 2x35x24x+22x^3 - 5x^2 - 4x + 2, and our remainder is **10**.

STEP 9

We write the final answer as 2x35x24x+2+10x62x^3 - 5x^2 - 4x + 2 + \frac{10}{x - 6}.

STEP 10

2x35x24x+2+10x62x^3 - 5x^2 - 4x + 2 + \frac{10}{x - 6}

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