Math  /  Algebra

QuestionWarren runs races to support local charities. In April, he ran a 5-kilometer race in 30 minutes to support his local hospital. In October, he will run a 10-kilometer race to support the animal shelter. If he runs at the same rate, how many minutes will it take Warren to run the race in October?

Studdy Solution

STEP 1

What is this asking? If Warren runs twice the distance at the same speed, how much longer will it take? Watch out! Don't forget that the distances are different!
We need to figure out how much longer the second race is compared to the first race.

STEP 2

1. Calculate Warren's speed
2. Calculate the time for the October race

STEP 3

Alright, let's **start** by figuring out how fast Warren runs.
Speed is just distance divided by time.
We know Warren ran 55 kilometers in 3030 minutes.

STEP 4

So, his speed is 5 km/30 min5 \text{ km} / 30 \text{ min}.
Let's simplify that fraction by dividing both the **top** and **bottom** by 55.
This gives us 1 km/6 min1 \text{ km} / 6 \text{ min}.
That means Warren runs **one kilometer every six minutes**!

STEP 5

Now, we know the October race is 1010 kilometers.
Since we know Warren's speed, we can figure out how long it will take him.

STEP 6

We can set up a simple equation: time=distance/speed\text{time} = \text{distance} / \text{speed}.
We **plug in** our values: time=10 km/(1 km/6 min)\text{time} = 10 \text{ km} / (1 \text{ km} / 6 \text{ min}).

STEP 7

Dividing by a fraction is the same as multiplying by its reciprocal, so we flip the fraction and multiply: time=10 km(6 min/1 km)\text{time} = 10 \text{ km} \cdot (6 \text{ min} / 1 \text{ km}).

STEP 8

Notice how the "km" units **cancel out** by dividing to one, leaving us with: time=106 min\text{time} = 10 \cdot 6 \text{ min}.

STEP 9

Multiplying 1010 and 66 gives us 6060.
So, the **time** is 6060 minutes!

STEP 10

It will take Warren **60 minutes** to run the 10-kilometer race in October.

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