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Math  /  Trigonometry

QuestionUse your calculator to evaluate each expression. Give answers in degrees, rounded to 1 decimal place. sin⁡−1(−0.25)=□cos⁡−1(0.48)=□tan⁡−1(6)=□\begin{array}{l} \sin ^{-1}(-0.25)=\square \\ \cos ^{-1}(0.48)=\square \\ \tan ^{-1}(6)=\square \end{array}
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Studdy Solution

STEP 1

1. We are using a calculator to find the inverse trigonometric functions.
2. The answers should be in degrees, rounded to one decimal place.
3. The inverse trigonometric functions will provide angles whose sine, cosine, or tangent is the given value.

STEP 2

1. Evaluate sin⁡−1(−0.25)\sin^{-1}(-0.25) using a calculator.
2. Evaluate cos⁡−1(0.48)\cos^{-1}(0.48) using a calculator.
3. Evaluate tan⁡−1(6)\tan^{-1}(6) using a calculator.

STEP 3

Use a calculator to find sin⁡−1(−0.25)\sin^{-1}(-0.25):
1. Ensure the calculator is set to degree mode.
2. Enter −0.25-0.25 and use the inverse sine function.
The result is approximately:
sin⁡−1(−0.25)≈−14.5∘ \sin^{-1}(-0.25) \approx -14.5^\circ

STEP 4

Use a calculator to find cos⁡−1(0.48)\cos^{-1}(0.48):
1. Ensure the calculator is set to degree mode.
2. Enter 0.480.48 and use the inverse cosine function.
The result is approximately:
cos⁡−1(0.48)≈61.4∘ \cos^{-1}(0.48) \approx 61.4^\circ

STEP 5

Use a calculator to find tan⁡−1(6)\tan^{-1}(6):
1. Ensure the calculator is set to degree mode.
2. Enter 66 and use the inverse tangent function.
The result is approximately:
tan⁡−1(6)≈80.5∘ \tan^{-1}(6) \approx 80.5^\circ
The evaluated expressions are:
sin⁡−1(−0.25)≈−14.5∘cos⁡−1(0.48)≈61.4∘tan⁡−1(6)≈80.5∘\begin{array}{l} \sin^{-1}(-0.25) \approx -14.5^\circ \\ \cos^{-1}(0.48) \approx 61.4^\circ \\ \tan^{-1}(6) \approx 80.5^\circ \end{array}

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