Math  /  Algebra

QuestionUse the given conditions to write an equation for the line in point-slope form and in slope-intercept form. Passing through (9,6)(9,-6) and perpendicular to the line whose equation is y=15x+5y=\frac{1}{5} x+5
Write an equation for the line in point-slope form. \square (Simplify your answer. Use integers or fractions for any numbers in the equation.) Write an equation for the line in slope-intercept form. \square (Simplify your answer. Use integers or fractions for any numbers in the equation.)

Studdy Solution

STEP 1

1. We need to find the equation of a line passing through the point (9,6) (9, -6) .
2. The line is perpendicular to the given line y=15x+5 y = \frac{1}{5}x + 5 .
3. We need to write the equation in both point-slope form and slope-intercept form.

STEP 2

1. Determine the slope of the line perpendicular to the given line.
2. Use the point-slope form to write the equation of the line.
3. Convert the point-slope form equation to slope-intercept form.

STEP 3

Determine the slope of the line perpendicular to the given line.
The slope of the given line is 15 \frac{1}{5} .
For two lines to be perpendicular, the product of their slopes must be 1-1. Let m m be the slope of the line we are trying to find:
m×15=1 m \times \frac{1}{5} = -1
Solve for m m :
m=1×5 m = -1 \times 5 m=5 m = -5
The slope of the line we are looking for is 5 -5 .

STEP 4

Use the point-slope form to write the equation of the line.
The point-slope form of a line is given by:
yy1=m(xx1) y - y_1 = m(x - x_1)
Substitute m=5 m = -5 and the point (9,6) (9, -6) :
y(6)=5(x9) y - (-6) = -5(x - 9)
Simplify:
y+6=5(x9) y + 6 = -5(x - 9)
This is the equation of the line in point-slope form.

STEP 5

Convert the point-slope form equation to slope-intercept form.
Start with the point-slope form:
y+6=5(x9) y + 6 = -5(x - 9)
Distribute the 5-5:
y+6=5x+45 y + 6 = -5x + 45
Subtract 6 from both sides to solve for y y :
y=5x+456 y = -5x + 45 - 6 y=5x+39 y = -5x + 39
This is the equation of the line in slope-intercept form.

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