Math  /  Algebra

QuestionUse the given conditions to write an equation for the line in point-slope form. 12) Passing through (8,8)(8, 8) and (6,5)(6, 5)

Studdy Solution

STEP 1

What is this asking? We need to find the equation of a line that goes through two specific points, and we want that equation in point-slope form. Watch out! Don't mix up the xx and yy coordinates!
Also, remember point-slope form is yy1=m(xx1)y - y_1 = m(x - x_1), not y=mx+by = mx + b.

STEP 2

1. Find the slope.
2. Write the equation.

STEP 3

Alright, let's **start** by finding the slope!
The slope, which we usually call mm, tells us how steep our line is.
The formula for the slope between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is: m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1}

STEP 4

Our two points are (8,8)(8, 8) and (6,5)(6, 5).
Let's **label** these points to avoid confusion!
We'll call (8,8)(8, 8) our (x1,y1)(x_1, y_1) and (6,5)(6, 5) our (x2,y2)(x_2, y_2).
So, x1=8x_1 = 8, y1=8y_1 = 8, x2=6x_2 = 6, and y2=5y_2 = 5.

STEP 5

Now, let's **plug** these values into our slope formula: m=5868 m = \frac{5 - 8}{6 - 8}

STEP 6

**Calculate** the differences: m=32 m = \frac{-3}{-2}

STEP 7

**Simplify** the fraction by dividing both numerator and denominator by 1-1: m=32 m = \frac{3}{2} So, our **slope** is 32\frac{3}{2}!

STEP 8

Now that we have our slope, we can use the **point-slope form** of a linear equation, which is: yy1=m(xx1) y - y_1 = m(x - x_1)

STEP 9

We already have our slope m=32m = \frac{3}{2} and we can use either of our points for (x1,y1)(x_1, y_1).
Let's use (8,8)(8, 8), so x1=8x_1 = 8 and y1=8y_1 = 8.

STEP 10

**Substitute** these values into the point-slope form: y8=32(x8) y - 8 = \frac{3}{2}(x - 8) And there we have it!

STEP 11

The equation of the line in point-slope form passing through (8,8)(8, 8) and (6,5)(6, 5) is y8=32(x8)y - 8 = \frac{3}{2}(x - 8).

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