Math

QuestionEvaluate the function f(x)=x2x27f(x)=\frac{\sqrt{x-2}}{x^{2}-7} for x=19x=19, x=5x=-5, and x=3.7x=3.7. Determine if each is defined.

Studdy Solution

STEP 1

Assumptions1. The function is defined as f(x)=xx7f(x)=\frac{\sqrt{x-}}{x^{}-7} . We need to evaluate the function at x=19x=19, x=5x=-5, and x=3.7x=3.7

STEP 2

First, let's evaluate f(19)f(19). We can do this by substituting x=19x=19 into the function.
f(19)=1921927f(19)=\frac{\sqrt{19-2}}{19^{2}-7}

STEP 3

implify the expression inside the square root and the denominator.
f(19)=173617f(19)=\frac{\sqrt{17}}{361-7}

STEP 4

Calculate the denominator.
f(19)=17354f(19)=\frac{\sqrt{17}}{354}

STEP 5

Now, let's evaluate f(5)f(-5). We can do this by substituting x=5x=-5 into the function.
f(5)=52(5)27f(-5)=\frac{\sqrt{-5-2}}{(-5)^{2}-7}

STEP 6

implify the expression inside the square root and the denominator.
f(5)=25f(-5)=\frac{\sqrt{-}}{25-}

STEP 7

Since the square root of a negative number is undefined in the real number system, we can conclude that f(5)f(-5) is undefined.

STEP 8

Finally, let's evaluate f(3.7)f(3.7). We can do this by substituting x=3.7x=3.7 into the function.
f(3.7)=3.72(3.7)27f(3.7)=\frac{\sqrt{3.7-2}}{(3.7)^{2}-7}

STEP 9

implify the expression inside the square root and the denominator.
f(3.7)=.7(3.7)27f(3.7)=\frac{\sqrt{.7}}{(3.7)^{2}-7}

STEP 10

Calculate the denominator.
f(3.7)=.713.697f(3.7)=\frac{\sqrt{.7}}{13.69-7}

STEP 11

Calculate the final value.
f(3.7)=.76.69f(3.7)=\frac{\sqrt{.7}}{6.69}So, the answers are(a) f(19)=17354f(19)=\frac{\sqrt{17}}{354} (b) f(5)f(-5) is undefined. (c) f(3.7)=.76.69f(3.7)=\frac{\sqrt{.7}}{6.69}

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