Math  /  Algebra

QuestionUse the function f(x)=3x15f(x)=3^{x-1}-5 to answer the following: (a) Determine the equation of the asymptote of f(x)f(x).
Your answer should include y=y= or x=x= \square (b) Determine the domain of f(x)f(x) in interval notation. \square (c) Determine the range of f(x)f(x) in interval notation. \square

Studdy Solution

STEP 1

1. The function f(x)=3x15 f(x) = 3^{x-1} - 5 is an exponential function.
2. Exponential functions of the form ax a^{x} have horizontal asymptotes.
3. The domain of exponential functions is typically all real numbers.
4. The range of an exponential function ax+c a^{x} + c is affected by the vertical shift c c .

STEP 2

1. Determine the equation of the asymptote.
2. Determine the domain of f(x) f(x) .
3. Determine the range of f(x) f(x) .

STEP 3

To find the horizontal asymptote of the function f(x)=3x15 f(x) = 3^{x-1} - 5 , we consider the behavior of the exponential part 3x1 3^{x-1} as x x approaches negative infinity.
For exponential functions of the form ax a^{x} , as x x \to -\infty , ax0 a^{x} \to 0 .
Thus, the horizontal asymptote is determined by the constant term in the function, which is:
y=5 y = -5

STEP 4

The domain of the function f(x)=3x15 f(x) = 3^{x-1} - 5 is determined by the values of x x for which the function is defined.
Since exponential functions are defined for all real numbers, the domain is:
(,) (-\infty, \infty)

STEP 5

To determine the range of f(x)=3x15 f(x) = 3^{x-1} - 5 , we consider the transformation of the basic exponential function 3x 3^{x} .
The function 3x1 3^{x-1} is a horizontal shift of 3x 3^{x} , and subtracting 5 shifts the entire graph down by 5 units.
The range of 3x 3^{x} is (0,) (0, \infty) , so the range of 3x15 3^{x-1} - 5 is:
(5,) (-5, \infty)
(a) The equation of the asymptote is y=5 y = -5 . (b) The domain of f(x) f(x) is (,) (-\infty, \infty) . (c) The range of f(x) f(x) is (5,) (-5, \infty) .

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