Math  /  Trigonometry

Question. Use Technology a) Predict the form of the graph of y=tanx+2y=\tan x+2.
Verify your prediction using graphing technology. b) Predict the form of the graph of y=3tanxy=3 \tan x.
Verify your prediction using graphing 24. technology. c) Predict the form of the graph of y=tan(xπ4)y=\tan \left(x-\frac{\pi}{4}\right). Verify your prediction using graphing technology. d) Predict the form of the graph of y=tan3xy=\tan 3 x. Verify your prediction using graphing technology.

Studdy Solution

STEP 1

1. We are working with transformations of the basic tangent function y=tanx y = \tan x .
2. The tangent function has a period of π \pi and vertical asymptotes at x=π2+kπ x = \frac{\pi}{2} + k\pi for integer k k .
3. Transformations include vertical shifts, vertical stretches/compressions, horizontal shifts, and changes in period.

STEP 2

1. Predict the form of the graph of y=tanx+2 y = \tan x + 2 .
2. Predict the form of the graph of y=3tanx y = 3 \tan x .
3. Predict the form of the graph of y=tan(xπ4) y = \tan \left(x - \frac{\pi}{4}\right) .
4. Predict the form of the graph of y=tan3x y = \tan 3x .

STEP 3

a) Predict the form of the graph of y=tanx+2 y = \tan x + 2 :
- The graph of y=tanx y = \tan x is vertically shifted upwards by 2 units. - The vertical asymptotes remain unchanged at x=π2+kπ x = \frac{\pi}{2} + k\pi .

STEP 4

b) Predict the form of the graph of y=3tanx y = 3 \tan x :
- The graph of y=tanx y = \tan x is vertically stretched by a factor of 3. - The vertical asymptotes remain unchanged at x=π2+kπ x = \frac{\pi}{2} + k\pi . - The amplitude of the tangent graph is not defined, but the steepness of the graph increases.

STEP 5

c) Predict the form of the graph of y=tan(xπ4) y = \tan \left(x - \frac{\pi}{4}\right) :
- The graph of y=tanx y = \tan x is horizontally shifted to the right by π4 \frac{\pi}{4} units. - The vertical asymptotes shift to x=π2+π4+kπ x = \frac{\pi}{2} + \frac{\pi}{4} + k\pi .

STEP 6

d) Predict the form of the graph of y=tan3x y = \tan 3x :
- The period of the tangent function changes from π \pi to π3 \frac{\pi}{3} . - The vertical asymptotes are now at x=π6+kπ3 x = \frac{\pi}{6} + \frac{k\pi}{3} .
Verify each prediction using graphing technology to ensure the transformations are accurately represented.

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