Math

QuestionUngkapkan 3×74+2×73+53 \times 7^{4}+2 \times 7^{3}+5 dalam bentuk nombor asas tujuh.

Studdy Solution

STEP 1

Assumptions1. We are given the expression 3×74+×73+53 \times7^{4}+ \times7^{3}+5 . We need to express this number in base7

STEP 2

First, we need to calculate the value of the given expression.
×74+2×7+5 \times7^{4}+2 \times7^{}+5

STEP 3

Calculate the value of 77^{} and 737^{3}.
7=24017^{} =240173=3437^{3} =343

STEP 4

Substitute the values of 747^{4} and 737^{3} into the expression.
3×2401+2×343+3 \times2401+2 \times343+

STEP 5

Calculate the value of the expression.
3×2401+2×343+5=7203+686+5=78943 \times2401+2 \times343+5 =7203 +686 +5 =7894

STEP 6

Now, we need to convert the decimal number7894 to base. We do this by repeatedly dividing by and keeping track of the remainders.

STEP 7

Divide7894 by7 and keep track of the remainder.
7894÷7=1127remainder57894 \div7 =1127 \, remainder \,5

STEP 8

Divide the quotient from the previous step by7 and keep track of the remainder.
1127÷7=161remainder01127 \div7 =161 \, remainder \,0

STEP 9

Continue this process until the quotient is less than7.
161÷7=23remainder161 \div7 =23 \, remainder \,23÷7=3remainder223 \div7 =3 \, remainder \,23÷7=remainder33 \div7 = \, remainder \,3

STEP 10

The number in base7 is the remainders read in reverse order.
Thenumberinbase7=32005The \, number \, in \, base \,7 =32005The number 3×74+2×73+53 \times7^{4}+2 \times7^{3}+5 in base7 is 32005732005_{7}.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord