Math

QuestionSolve the equation 2(2y1)=382(2y - 1) = 38.

Studdy Solution

STEP 1

Assumptions1. The given equation is (y1)=38(y-1)=38 . We need to solve for yy

STEP 2

First, we need to distribute the 22 on the left side of the equation.
2(2y1)=2×2y2×12(2y-1) =2 \times2y -2 \times1

STEP 3

Calculate the result of the distribution.
2×2y2×1=y22 \times2y -2 \times1 =y -2

STEP 4

Now, we replace the left side of the original equation with the result of the distribution.
4y2=384y -2 =38

STEP 5

Next, we need to isolate 4y4y on the left side of the equation. We can do this by adding 22 to both sides of the equation.
4y2+2=38+24y -2 +2 =38 +2

STEP 6

Calculate the result of the addition.
4y=404y =40

STEP 7

Finally, we need to solve for yy. We can do this by dividing both sides of the equation by 44.
y=404y = \frac{40}{4}

STEP 8

Calculate the value of yy.
y=404=10y = \frac{40}{4} =10So, the solution to the equation 2(2y1)=382(2y-1)=38 is y=10y =10.

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