Math

QuestionFind the least number of decimal places in a factor xx if xn=34.44x \cdot n = 34.44 and nn is a whole number.

Studdy Solution

STEP 1

Assumptions1. The product of the two factors is34.44. One factor is a whole number3. We need to find the least number of decimal places in the other factor

STEP 2

First, we need to express the product in terms of its factors. Let's denote the whole number as aa and the other factor as bb.atimesb=34.44a \\times b =34.44

STEP 3

Since we know that one factor is a whole number, we can start by assuming the smallest possible whole number, which is1.a=1a =1

STEP 4

Now, we can solve for bb by dividing the product by aa.
b=34.44ab = \frac{34.44}{a}

STEP 5

Substitute a=1a =1 into the equation to find bb.
b=34.441b = \frac{34.44}{1}

STEP 6

Calculate the value of bb.
b=34.44b =34.44

STEP 7

Now, we can count the number of decimal places in bb. The number34.44 has two decimal places.
So, the least number of decimal places in the other factor is2.

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