QuestionSolve for $h$ in the equation: $\frac{2}{5} h - 7 = \frac{12}{5} h - 2h + 3$ .

Studdy Solution

STEP 1

Assumptions1. The given equation is $\frac{}{5} h-7=\frac{12}{5} h- h+3$ . We are solving for the variable $h$

STEP 2

First, we need to simplify the right side of the equation. We can do this by combining like terms.
$\frac{12}{5} h-2 h+ = \frac{12}{5} h - \frac{10}{5} h +$

STEP 3

Now, simplify the right side of the equation.
$\frac{12}{5} h - \frac{10}{5} h +3 = \frac{2}{5} h +3$

STEP 4

Now we have a simpler equation $\frac{2}{} h-7=\frac{2}{} h+3$

STEP 5

Subtract $\frac{2}{5} h$ from both sides of the equation to eliminate $h$ on one side.
$\frac{2}{5} h - \frac{2}{5} h -7 = \frac{2}{5} h - \frac{2}{5} h +3$

STEP 6

implify both sides of the equation.
$- =3$

STEP 7

This equation is not possible, as -7 does not equal3. Therefore, there is no solution for the variable $h$ in the given equation.

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QuestionSolve for $h$ in the equation: $\frac{2}{5} h - 7 = \frac{12}{5} h - 2h + 3$ .

Studdy Solution

STEP 1

Assumptions1. The given equation is $\frac{}{5} h-7=\frac{12}{5} h- h+3$ . We are solving for the variable $h$

STEP 2

First, we need to simplify the right side of the equation. We can do this by combining like terms.
$\frac{12}{5} h-2 h+ = \frac{12}{5} h - \frac{10}{5} h +$

STEP 3

Now, simplify the right side of the equation.
$\frac{12}{5} h - \frac{10}{5} h +3 = \frac{2}{5} h +3$

STEP 4

Now we have a simpler equation $\frac{2}{} h-7=\frac{2}{} h+3$

STEP 5

Subtract $\frac{2}{5} h$ from both sides of the equation to eliminate $h$ on one side.
$\frac{2}{5} h - \frac{2}{5} h -7 = \frac{2}{5} h - \frac{2}{5} h +3$

STEP 6

implify both sides of the equation.
$- =3$

STEP 7

This equation is not possible, as -7 does not equal3. Therefore, there is no solution for the variable $h$ in the given equation.

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QuestionSolve for hhh in the equation: 25h−7=125h−2h+3\frac{2}{5} h - 7 = \frac{12}{5} h - 2h + 352​h−7=512​h−2h+3.

Studdy Solution

STEP 1

Assumptions1. The given equation is 5h−7=125h−h+3\frac{}{5} h-7=\frac{12}{5} h- h+35​h−7=512​h−h+3 . We are solving for the variable hhh

STEP 2

First, we need to simplify the right side of the equation. We can do this by combining like terms.125h−2h+=125h−105h+\frac{12}{5} h-2 h+ = \frac{12}{5} h - \frac{10}{5} h +512​h−2h+=512​h−510​h+

STEP 3

Now, simplify the right side of the equation.125h−105h+3=25h+3\frac{12}{5} h - \frac{10}{5} h +3 = \frac{2}{5} h +3512​h−510​h+3=52​h+3

STEP 4

Now we have a simpler equation 2h−7=2h+3\frac{2}{} h-7=\frac{2}{} h+32​h−7=2​h+3

STEP 5

Subtract 25h\frac{2}{5} h52​h from both sides of the equation to eliminate hhh on one side.25h−25h−7=25h−25h+3\frac{2}{5} h - \frac{2}{5} h -7 = \frac{2}{5} h - \frac{2}{5} h +352​h−52​h−7=52​h−52​h+3

STEP 6

implify both sides of the equation.−=3- =3−=3

STEP 7

This equation is not possible, as -7 does not equal3. Therefore, there is no solution for the variable hhh in the given equation.

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Studdy solves anything!

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionSolve for $h$ in the equation: $\frac{2}{5} h - 7 = \frac{12}{5} h - 2h + 3$ .

Assumptions1. The given equation is $\frac{}{5} h-7=\frac{12}{5} h- h+3$ . We are solving for the variable $h$

First, we need to simplify the right side of the equation. We can do this by combining like terms.
$\frac{12}{5} h-2 h+ = \frac{12}{5} h - \frac{10}{5} h +$

Now, simplify the right side of the equation.
$\frac{12}{5} h - \frac{10}{5} h +3 = \frac{2}{5} h +3$

Now we have a simpler equation $\frac{2}{} h-7=\frac{2}{} h+3$

Subtract $\frac{2}{5} h$ from both sides of the equation to eliminate $h$ on one side.
$\frac{2}{5} h - \frac{2}{5} h -7 = \frac{2}{5} h - \frac{2}{5} h +3$

implify both sides of the equation.
$- =3$

This equation is not possible, as -7 does not equal3. Therefore, there is no solution for the variable $h$ in the given equation.