Math

Question Find the temperature range that Andrew considers comfortable. Write an absolute value equation to represent the situation, then solve for the minimum and maximum temperatures.
Part A: T70F5F|T - 70^{\circ} \mathrm{F}| \leq 5^{\circ} \mathrm{F} Part B: Minimum: 65F65^{\circ} \mathrm{F}, Maximum: 75F75^{\circ} \mathrm{F}

Studdy Solution

STEP 1

Assumptions
1. Andrew wants the temperature to be 70F70^{\circ}F.
2. The temperature can vary by plus or minus 5 degrees.
3. We need to write an absolute value equation to represent the situation.
4. We need to solve the equation to find the minimum and maximum temperatures.

STEP 2

Part A requires us to write an absolute value equation. The absolute value of a number represents its distance from zero on the number line, regardless of direction. In this case, the distance from the desired temperature (70F70^{\circ}F) can be at most 5 degrees in either direction.
TemperatureDesiredTemperature=MaximumVariation|Temperature - Desired\, Temperature| = Maximum\, Variation

STEP 3

Now, plug in the values for the desired temperature and the maximum variation to create the equation.
Temperature70F=5F|Temperature - 70^{\circ}F| = 5^{\circ}F

STEP 4

This is the absolute value equation that represents the situation.
T70=5|T - 70| = 5
Where TT is the actual temperature of Andrew's apartment.

STEP 5

Part B requires us to solve the absolute value equation to find the minimum and maximum temperatures.
An absolute value equation x=a|x| = a has two solutions: x=ax = a and x=ax = -a. Applying this to our equation:
T70=5orT70=5T - 70 = 5 \quad \text{or} \quad T - 70 = -5

STEP 6

First, solve the equation where the temperature is 5 degrees more than the desired temperature.
T70=5T - 70 = 5

STEP 7

Add 70 to both sides of the equation to solve for TT.
T=5+70T = 5 + 70

STEP 8

Calculate the value of TT.
T=75T = 75
This is the maximum temperature for Andrew's apartment.

STEP 9

Now, solve the equation where the temperature is 5 degrees less than the desired temperature.
T70=5T - 70 = -5

STEP 10

Add 70 to both sides of the equation to solve for TT.
T=5+70T = -5 + 70

STEP 11

Calculate the value of TT.
T=65T = 65
This is the minimum temperature for Andrew's apartment.
Minimum: 65F65^{\circ}F Maximum: 75F75^{\circ}F

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