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Math

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PROBLEM

What function represents the world's population P (in billions) tt years after 1975, given a 1.9% growth rate?
A) P(t)=4(1.019)tP(t)=4(1.019)^{t}
B) P(t)=4(1.9)tP(t)=4(1.9)^{t}
C) P(t)=1.19t+4P(t)=1.19 t+4

STEP 1

Assumptions1. The world's population growth rate is1.9% per year since1945. The world's population was approximately4 billion in19753. We are looking for a function that represents the world's population, in billions of people, t years since19754. The growth is exponential, not linear

STEP 2

The general form of an exponential function is(t)=0×(1+r)t(t) =0 \times (1 + r)^twhere- (t)(t) is the population at time tt,
- 00 is the initial population,
- rr is the growth rate, and- tt is the time since the initial population was measured.

STEP 3

Given that the world's population was approximately billion in1975, we can set 0=0 =.

STEP 4

The growth rate is given as1.9% per year. In the exponential function, this rate needs to be expressed as a decimal. So, we convert1.9% to0.019.

STEP 5

Substituting the values of 00 and rr into the exponential function, we get(t)=4×(1+0.019)t(t) =4 \times (1 +0.019)^t

SOLUTION

implify the expression inside the parentheses(t)=4×(1.019)t(t) =4 \times (1.019)^tThis function represents the world's population, in billions of people, t years since1975. Therefore, the correct answer is A) (t)=4(1.019)t(t)=4(1.019)^{t}.

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