Math  /  Algebra

QuestionThe wheel and piston device shown above consists of a wheel of radius 1 foot that is connected at the point W\mathbf{W} to a piston at P\mathbf{P} by a connecting rod (represented by the segment WP in the diagram) of length 8 feet. The wheel rotates counterclockwise at a rate of of 4 radians per second as the piston moves up and down along the yy-axis. (Click the hint to see animation). The point W\mathbf{W} is at (1,0)(1,0) at t=0t=0 seconds. a) What is the measure of angle θ\theta after tt seconds? θ=\theta=

Studdy Solution

STEP 1

What is this asking? We need to find the angle of the wheel after a certain amount of time, knowing how fast it's spinning. Watch out! Make sure to use radians, not degrees, since the rotation speed is given in radians per second.

STEP 2

1. Relate angle to time

STEP 3

We're given that the wheel rotates at a rate of **4 radians per second**.
This is our **rate of change**.

STEP 4

We can write this relationship mathematically as: Angle=RateTime\text{Angle} = \text{Rate} \cdot \text{Time}

STEP 5

Let θ\theta be the angle.
The rate is given as **4 radians per second**, and the time is represented by tt seconds.
So, after tt seconds, the angle θ\theta is: θ=4t\theta = 4 \cdot t Where θ\theta is in radians.

STEP 6

At t=0t = 0, the point W\mathbf{W} is at (1,0)(1, 0), which means the initial angle is **0 radians**.
Our formula already accounts for this, since when t=0t = 0, θ=40=0\theta = 4 \cdot 0 = 0.
So, we're good to go!

STEP 7

The angle θ\theta after tt seconds is given by: θ=4t\theta = 4t

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